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strojnjashka [21]
3 years ago
11

How do I answer my question

Mathematics
1 answer:
pychu [463]3 years ago
5 0
Sorry to say this but what do u even mean by HOW DO I ANSWER MY QUESTION
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Do you mean y = mx + b instead of y = mc + b? In that case:

b in y = mx + b format is the y-intercept, as this kind of equation is called slope-intercept form.

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A researcher wishes to estimate the proportion of adults who have​ high-speed Internet access. What size sample should be obtain
slega [8]

Answer: 8359

Step-by-step explanation:

The formula for sample size needed for interval estimate of population proportion :-

n=p(1-p)(\frac{z_{\alpha/2}}{E})^2

Given : The significance level : \alpha=1-0.95=0.05

Critical value : z_{\alpha/2}}=z_{0.025}=\pm1.96

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Margin of error : E=0.01

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n=0.32(1-0.32)(\frac{1.96}{0.01})^2=8359.3216\approx8359

Hence, the required sample size = 8359

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3 years ago
Please Help Asap Please And Thank You!
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Draw a picture of the standard normal curve and shade the area that corresponds to the requested probabilities. Then use the sta
elena-14-01-66 [18.8K]

Answer:

a)P [ z > 1,38 ] = 0,08379

b) P [ 1,233 < z < 2,43 ]  = 0,1012

c)  P [ z > -2,43 ]  = 0,99245

Step-by-step explanation:

a) P [ z > 1,38 ] = 1 -  P [ z < 1,38 ]

From z-table  P [ z < 1,38 ] = 0,91621

P [ z > 1,38 ] = 1 - 0,91621

P [ z > 1,38 ] = 0,08379

b)  P [ 1,233 - 2,43 ]  must be  P [ 1,233 < z < 2,43 ]

P [ 1,233 < z < 2,43 ]  = P [ z < 2,43 ] - P [ z > 1,233 ]

P [ z < 2,43 ]  = 0,99245

P [ z > 1,233 ] = 0,89125    ( approximated value  without interpolation)

Then

P [ 1,233 < z < 2,43 ]  = 0,99245 - 0,89125

P [ 1,233 < z < 2,43 ]  = 0,1012

c) P [ z > -2,43 ]

Fom z-table

P [ z > -2,43 ] = 1 - P [ z < -2,43 ]

P [ z > -2,43 ] = 1 - 0,00755

P [ z > -2,43 ]  = 0,99245

8 0
2 years ago
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