The weight of items produced by a machine is normally distributed with a mean of 8 ounces and a standard deviation of 2 ounces. what is the probability that a randomly selected item will weigh more than 10 ounces?
1 answer:
<span>First we calculate z using the formula:
z = (x - μ)/σ</span>
Where:
x = our variable, 10
μ = mean, 8
σ = standard dev, 2
Substituting known
values:<span>
z = (10 - 8)/2
z = 2/2
z = 1
Using the tables of
the normal distribution to find the p-value with z = 1
p = 0.8413
Since we want
"greater than 10”, we need to subtract the probability from 1
therefore
p* = 1 - 0.8413 = <span>0.1587</span> </span>
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