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3 years ago

The triangles are similar.

Mathematics

1 answer:

timurjin [86]3 years ago

4 0

Answer:

Step-by-step explanation:

You can do it two different ways.

1st. Find the scale factor by dividing - 75/25=3 or 72/24=3

This means the scale factor is three

Then multiply the remaining side (7) by the scale factor (3) to get: 21

2nd. Use the Pythagorean Theorem - 75²-72²=x²

441 = x²

√441=x

x=21

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Find the sum <br> (-8z+4)+(8z-7)

padilas [110]

Answer:

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Step-by-step explanation:

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2 years ago

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Solve cot x + 2cot x * sin x = 0 for U^ <= x<=180

nekit [7.7K]

Answer:

Step-by-step explanation:

hello :

cot x + 2cot x sin x = 0 0≤ x≤ 180

cotx(1+2sinx) =0 means : cotx=0 or 1+2sinx=0

1) cotx=0 so : cosx=0 and sinx ≠ 0 because cotx = cosx/sinx

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2 years ago

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3 years ago

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The graphs below have the same shape the equation of the red graph is f(x) =x^2. What is the equation of the blue graph?

daser333 [38]

Answer:

$G(x)=(x-6)^2$

which agrees with the answer D of your options

Step-by-step explanation:

Notice that the graph of G(x) has the initial graph shifted horizontally to the right in 6 units, therefore such horizontal shift is accomplished by subtracting the 6 units from the x-variable in the original expression:

$G(x)=(x-6)^2$

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2 years ago

A sandbox has an area of 10 2/3 square feet, and the length is 1/4 feet. What is the width of the sandbox?

AlekseyPX

Answer:

The width of the sandbox is $42\frac{2}{3} \ ft$ .

Step-by-step explanation:

Given,

Area of the sandbox = $10\frac{2}{3}=\frac{32}{3}\ ft^2$

Length = $\frac{1}{4}\ ft$

Solution,

Let the width of the sandbox be 'w'.

Since the sandbox is in shape of rectangle.

So we use the formula of area of rectangle.

$Area = Length\times Width$

On substituting the given values, we get;

$\frac{1}{4}\times w=\frac{32}{3}\\$

By cross multiplication method, we get;

$w=\frac{32\times4}{3\times 1} =\frac{128}{3} =42\frac{2}{3} \ ft$

Hence The width of the sandbox is $42\frac{2}{3} \ ft$ .

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3 years ago