5.3 minutes.
First, let's calculate the volume of the tank. That will be the area of the base multiplied by it's length. And since it's base is a circle, the area is pi*r^2. So:
V = l*pi*r^2
V = 3.5 * pi * (2.2/2)^2
V = 3.5 * pi * (1.1)^2
V = 3.5 * pi * 1.21
V = 4.235 * pi
V = 13.30464489
So the tank has a volume of about 13.3 ft^3. Now simply divide that volume
by the rate of incoming fluid. So
13.3 / 2.5 = 5.32
Rounding to 2 significant figures gives a time of 5.3 minutes.
A. 3/4 = 0.75 3/5 = 0.6 3/10 = 0.3 3/12 = 0.25
Right order
3/12 < 3/10 < 3/5 < 3/4
The right answer is letter D.
The segment goes from point (-1, 3) to (1,-1)
Slope = rise / run = (-3 - 1) / (1 - (-1)) = -4 / 2 = -2
Slope = -2
