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3 years ago

What is the volume? 9 cm 8cm 6 cm

Mathematics

2 answers:

vova2212 [387]3 years ago

6 0

Answer:

432cm^3

Step-by-step explanation:

Volume=l×b×h

=9×8×6

432cm^3

snow_lady [41]3 years ago

6 0

You would multiply all of them together and you would get 432cm^3

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Gus has skydived 4 more times than Nico. Emma has skydived twice as many times as Nico. If Emma has skydived 16 times, how many

Oliga [24]

32 times bc emma skydived 16 times and it says sue sky dived 2 × Nico so you would divide 16 ÷ 2 and get 8 then it says gus has skydived 4 times more than nico so you do 8 × 4 and get 32 as your answer

6 0

3 years ago

Convert the Cartesian equation x^2 + y^2 = 16 to a polar equation.

RideAnS [48]

Answer:

Problem 1: $r=4$

Problem 2: $r=-2\sin(\theta)$

Problem 3: $r\sin(\theta)=3$

Step-by-step explanation:

Problem 1:

So we are going to use the following to help us:

$x=r \cos(\theta)$

$y=r \sin(\theta)$

$\frac{y}{x}=\tan(\theta)$

So if we make those substitution into the first equation we get:

$x^2+y^2=16$

$(r\cos(\theta))^2+r\sin(\theta))^2=16$

$r^2\cos^2(\theta)+r^2\sin^2(\theta)=16$

Factor the $r^2$ out:

$r^2(\cos^2(\theta)+\sin^2(\theta))=16$

The following is a Pythagorean Identity: $\cos^2(\theta)+\sin^2(\theta)=1$ .

We will apply this identity now:

$r^2=16$

This implies:

$r=4 \text{ or } r=-4$

We don't need both because both of include points with radius 4.

Problem 2:

$x^2+y^2+2y=0$

$(r\cos(\theta))^2+(r\sin(\theta))^2+2(r\sin(\theta))=0$

$r^2\cos^2(\theta)+r^2\sin^2(\theta)+2r\sin(theta)=0$

Factoring out $r^2$ from first two terms:

$r^2(\cos^2(\theta)+\sin^2(\theta))+2r\sin(\theta)=0$

Apply the Pythagorean Identity I mentioned above from problem 1:

$r^2(1)+2r\sin(\theta)=0$

$r^2+2r\sin(\theta)=0$

or if we factor out r:

$r(r+2\sin(\theta))=0$

$r=0 \text{ or } r=-2\sin(\theta)$

r=0 is actually included in the other equation since when theta=0, r=0.

Problem 3:

$y=3$

$r\sin(\theta)=3$

8 0

3 years ago

AB = 6x DC = x + 15 AD = 9 BC = 3y Quadrilateral ABCD is a parallelogram if both pairs of opposite sides are congruent. Show tha

ra1l [238]

Answer:

Therefore the lengths of the opposite side pairs.

C) 18, 9

Step-by-step explanation:

Given:

Quadrilateral ABCD is a parallelogram

AB = 6x

DC = x + 15

AD = 9

BC = 3y

TO Find:

AB = ?

BC = ?

Solution:

Quadrilateral ABCD is a parallelogram ..........Given

∴ Both pairs of opposite sides of a Parallelogram are congruent.

∴ AB = DC and AD = BC

substituting the values we get

$6x=x+15\\6x-x=15\\5x=15\\x=\dfrac{15}{5}\\ x=3\\and\\9=3y\\y=\dfrac{9}{3}\\ y=3$

substituting the x' and 'y' values we get

$AB= 6\times 3=18\\and\\BC=3\times 3=9$

Therefore the lengths of the opposite side pairs.

C) 18, 9

3 0

3 years ago

HELPP PLZ DONT SEND A FILE WHATS THE ANWERS ASAP

Mariana [72]

The answer is 2990.8 yd

Formula for SA of cylinder: 2*pi*r*h+2*pi*r^2

Formula for radius: diameter/2

Plug the radius, 17, height, 11, and pi, 3.14, into the formula above.

= 2990.8 yd

4 0

2 years ago

Read 2 more answers

Simplify 6 + 7.2y - 4.2y + 1

jok3333 [9.3K]

Answer:

3y+7

Step-by-step explanation:

6+7.2y+−4.2y+1

(7.2y+−4.2y)+(6+1)

3y+7

5 0

2 years ago