Answer:
Local minimum at x = 0.
Step-by-step explanation:
Local minimums occur when g'(x) = 0 and g"(x) > 0.
Local maximums occur when g'(x) = 0 and g"(x) < 0.
Set g'(x) equal to 0 and solve:
0 = 2x (x − 1)² (x + 1)²
x = 0, 1, or -1
Evaluate g"(x) at each point:
g"(0) = 2
g"(1) = 0
g"(-1) = 0
There is a local minimum at x = 0.
I think b because i used a calculator
A, an irrational number would be something like 200.688965529290363892
23(3) + 3
= 72
Why do you write 2 equations?
Answer:
x = 4
Step-by-step explanation:
2x + 6 = 7x - 14
2x - 7x = - 14 - 6
-5x = -20
x = 4
