at the beginning of the month a store had a balance of -554. during the month the store lost another 600 what is the balance

A) Complete the table of values for y = 6 - 2x

GREYUIT [131]

Step-by-step explanation:

the answer as shown in the photo

3 0

2 years ago

In an equation y varies directly as x varies.If y =208 when x =13 what is the value of x when y=-144

MissTica

Hope this helped you with your problem

7 0

3 years ago

A runner runs 8 miles in 92 minutes what is the runner’s unit rate?

nikitadnepr [17]

Answer:

The runner's unit rate is 0.09 miles/minute.

Step-by-step explanation:

Given:

Distance cover by runner = 8 miles and the time taken = 92 minutes.

Now, to calculate the runner's unit rate.

We put the formula to get the unit rate:

Velocity = distance/time

$v=\frac{d}{t}$

$v=\frac{8}{92}$

$v=0.0869$

v = 0.09 miles/minute (approximately)

Therefore, the runner's unit rate is 0.09 miles/minute.

8 0

3 years ago

3. You invested $11,000 in stocks and bonds paying 5% and 8% annual interest. If the total interest for the year was $730, how m

castortr0y [4]

9514 1404 393

Answer:

3. $6000 at 8%; $5000 at 5%

4. 66 2/3 gallons of 9%; 133 1/3 gallons of 6%

Step-by-step explanation:

For many mixture problems, it works well to let a variable represent the amount of the largest contributor used in the mix.

3. Let x represent the amount invested at 8%. Then the total interest is ...

8%x +5%(11000-x) = 730

3%x = 730 -550

x = 180/0.03 = 6000

$6000 was invested at 8%; $5000 was invested at 5%.

__

4. Let x represent the number of gallons of 9% content. Then the alcohol content of the mix is ...

9%x +6%(200 -x) = 7%(200)

3%x = 1%(200) . . . . . subtract 6%(200)

x = 200/3 = 66 2/3 . . . . . divide by 3%

200 -x = 133 1/3

66 2/3 gallons of 9% wine and 133 1/3 gallons of 6% wine should be used.

5 0

2 years ago

SOMEONE PLZ HELP IM STRUGGLING ON HOMEWORK......15 PTS

kakasveta [241]

Answer:

Part A) A reasonable domain is the interval [0,7]

$0\leq m\leq 7$

Part B) see the explanation

Part C) The average rate of change is $0.45\ cm/month$

see the explanation

Step-by-step explanation:

Let

m ---> the number of months

f(m) ---> the length of the fish in cm

we have

$f(m)=4(1.08^m)$

This is a exponential function of the form

$f(m)=a(b^m)$

where

a is the initial value or y-intercept

b is the base of the exponential function

b=1+r

r is the percent average of change

In this problem we have

$a=4\ cm$

$b=1.08$

$r=1.08-1=0.08$

$r=0.08*100=8\%$

Part A) When the marine biologist concluded her study, the length of the fish was approximately 6.86 cm. What is a reasonable domain to plot the growth function?

For f(m)=6.86 cm

substitute the given value in the function

$6.86=4(1.08^m)$

solve for m

$1.715=(1.08^m)$

Apply log both sides

$log(1.715)=log(1.08^m)$

$log(1.715)=(m)log(1.08)$

$m=log(1.715)/log(1.08)$

$m=7\ months$

therefore

A reasonable domain is the interval [0,7]

$0\leq m\leq 7$

Part B) What does the y-intercept of the graph of the function f(m) represent?

we know that

The y-intercept is the value of the function when the value of m is equal to zero

In this context the y intercept is the initial value of the function, or the starting size of the fish at month 0

For m=0

$f(0)=4(1.08^0)$

$f(0)=4\ cm$

therefore

At the beginning of the study the length of the fish was 4 cm

Part C) What is the average rate of change of the function f(m) from m = 3 to m = 7, and what does it represent?

we know that

To find the average rate of change, we divide the change in the output value by the change in the input value

the average rate of change is equal to

$\frac{f(b)-f(a)}{b-a}$

In this problem we have

$a=3$

$b=7$

$f(a)=f(3)=4(1.08^3)=5.0388\ cm$

$f(b)=f(7)=4(1.08^7)=6.8553\ cm$

Substitute

$\frac{6.8553-5.0388}{7-3}=0.45\ cm/month$

The average rate of change is how fast the growth changed over the time period

4 0

3 years ago