Answer:
(1) manage the computer's resources, such as the central processing unit, memory, disk drives, and printers, (2) establish a user interface, and (3) execute and provide services for applications software.
Answer:
See explaination
Explanation:
Keep two iterators, i (for nuts array) and j (for bolts array).
while(i < n and j < n) {
if nuts[i] == bolts[j] {
We have a case where sizes match, output/return
}
else if nuts[i] < bolts[j] {
this means that size of nut is smaller than that of bolt and we should go to the next bigger nut, i.e., i+=1
}
else {
this means that size of bolt is smaller than that of nut and we should go to the next bigger bolt, i.e., j+=1
}
}
Since we go to each index in both the array only once, the algorithm take O(n) time.
Answer and Explanation:
Within the following operating mode, most of the wireless controller remains linked through the main point (access point) for that broader server. The server runs within ad-hoc modes when this does not run under the following mode. Wireless servers wouldn't have the connectivity to interact within ad-hoc mode.
So, the following statement is correct according to the given scenario of the following mode.
Answer:
Following are statement is given below
int k=1,total=0; // variable declaration
while(k<50) // iterating the while loop
{
total=total+k*k;// calculating the square
k=k+1; // increments the value of k by 1
}
Explanation:
Following are the description of Statement.
- Declared a variable "total" and "k" of the "integer " type initialized the total to 0 and "k" to 1.
- Iterating the while loop for less then 50 .In this loop, we calculating the sum of square of first 50 number in the "total" variable .
- After that increment the value of "k" variable by 1 to execute the loop less then 50 .
