Answer:
aaaa
Explanation:
We have a function nPrint which return type is void, it means it returns nothing.
we declare the two parameters, one parameter is string type and the second parameter is an integer type.
Then, it has a while loop that executes the statement again and again until the condition not FALSE.
Let dry run the code:
First, call the function nPrint("a", 4) bypassing the value in the argument.
then, the value receives by the parameters, the message contains "a" and n contain 4. After that, while loop checks the condition 4 > 0, which is TRUE and the program starts executing the statement.
The program prints the message on the screen "a" and then decreases the value of n by 1. So, the value of n becomes 3.
The above process repeats for the value of n = 3, 2, 1
and print the message "aaaa".
then, the condition becomes false and the program terminates the loop.
Therefore, the answer is aaaa
Answer:
hiii
Explanation:
kk ill follow you do you have any vids
Answer:
decode( )
Explanation:
We can use the method decode( ) to decode the string using the codec registered for encoding.
There are two parameters
encoding: We can encode with this parameter.
errors: If used to manage the errors.
For example:
String = "this is string example....wow!!!";
String = Str.encode('base64','strict');
If we print these variables we have:
String = b'dGhpcyBpcyBzdHJpbmcgZXhhbXBsZS4uLi53b3chISE='
String = this is string example....wow!!!
Answer:
Explanation:
try
clc
clear
close all
x=linspace(0,2*pi,7);
z=cos(pi.*x./3)
% the output on mine is to 4 decimals so it looks a bit different than what the output on your example is , but, I think if you change the format to decimal 2 it will look the same :)
