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Marina CMI [18]
3 years ago
6

Given: JK tangent, KH=16, HE=12 Find: JK.

Mathematics
1 answer:
grin007 [14]3 years ago
7 0

Check the picture below.

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What range of possible sizes for side x?
tiny-mole [99]

Answer:

1.4 I think

Step-by-step explanation:

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3 years ago
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Use the key features of the polynomial f(x) = -2x3 + 5x2 - 2x - 3 to describe its end behavior.
Andre45 [30]

Answer:

Step-by-step explanation:

First consider the parent function y = x^3 and its graph.  The left side starts in Quadrant III and continues up through Quadrant I.  A negative sign in front of the x^3 reflects this original graph in the x-axis; the graph now starts in Quadrant II and descends into Quadrant IV.

The end behavior of the given function is the same as that of the graph of y = -x^3;  

The graph begins in Quadrant II and descends into Quadrant IV, down.

8 0
3 years ago
Which diagram shows lines that must be parallel lines cut by a transversal?
eimsori [14]

9514 1404 393

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  2 horizontal lines are intersected by another line. At the intersection with the first line, the bottom right angle is 91 degrees. At the intersection with the second line, the top right angle is 89 degrees.

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The last of the statements describes consecutive (same-side) interior angles at the transversal that are supplementary. That condition exists when the lines are parallel.

7 0
3 years ago
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5.12÷ 102.<br><br> 512<br><br> 0.512<br><br> 0.00512<br><br> 0.0512
AveGali [126]

0.00512

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5 0
3 years ago
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Which function can be used to represent the graphed geometric sequence
11111nata11111 [884]
ANSWER

f(x)=80( \frac{1}{4}) ^{x-1}


EXPLANATION

The term of the sequence are;

80,20,5,...


The first term of the sequence is,

a_1=80



The common ratio is

r =  \frac{20}{80}

r =  \frac{1}{4}

The sequence is given by the formula


f(x)=a_1r^{x-1}


When we substitute the values into the formula we get,

f(x)=80( \frac{1}{4}) ^{x-1}


The correct answer is A
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3 years ago
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