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neonofarm [45]
3 years ago
14

It is found that there is a relationship between the weight of an airplane and the maximum speed it can travel. The results were

published claiming that a lighter airplane can travel faster. What is the problem with reporting the result this way?
Mathematics
2 answers:
Otrada [13]3 years ago
7 0
Missing data or correlation and causality
inn [45]3 years ago
6 0
That claim doesn't contain any numerical evidence.
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Pretest: Unit 1
Alex_Xolod [135]

A vertical line that the graph of a function approaches but never intersects. The correct option is B.

<h3>When do we get vertical asymptote for a function?</h3>

Suppose that we have the function f(x) such that it is continuous for all input values < a or > a and have got the values of f(x) going  to infinity or -ve infinity (from either side of   x = a) as x goes near a, and is not defined at   x = a, then at that point, there can be constructed a vertical line  x = a and it will be called as vertical asymptote for f(x) at   x = a

A vertical asymptote can be described as a vertical line that the graph of a function approaches but never intersects.

Hence, the correct option is B.

Learn more about Vertical Asymptotes:

brainly.com/question/2513623

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3 0
1 year ago
Graph the hyperbola using the transverse axis, vertices, and co-vertices:
Reptile [31]

See attachment for the graph of the hyperbola 12x^2 - 3y^2 - 108 = 0

<h3>How to graph the hyperbola?</h3>

The equation of the hyperbola is given as:

12x^2 - 3y^2 - 108 = 0

Start by calculating the transverse axis

So, we have:

<u>Transverse axis</u>

The vertices of the given hyperbola are (0, 0)

This means that

(h, k) = 0

Where

a = 3 and b = 6

The transverse axis is calculated as:

y = ±b/a(x - h) + k

So, we have:

y = ±6/3(x - 0) + 0

Evaluate the difference and sum

y = ±6/3x

Evaluate the quotient

y = ±2x

This means that the transverse axes are y = 2x and y =-2x

<u>The vertices</u>

In the above section, we have:

The vertices of the given hyperbola are (0, 0)

This means that

(h, k) = 0

<u>The co-vertices</u>

In the above section, we have:

The vertices of the given hyperbola are (0, 0)

This means that

(h, k) = 0

And

a = 3 and b = 6

The co-vertices are

(h - a, k) and (h + a, k)

So, we have:

(0 - 3, 0) and (0 + 3, 0)

Evaluate

(-3,0) and (3, 0)

See attachment for the graph of the hyperbola

Read more about hyperbola at:

brainly.com/question/26250569

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4 0
1 year ago
7. Big screen TV's are typically classified by the
Serggg [28]

Answer:100

Step-by-step explanation:

6 0
3 years ago
The daily high temperatures for two cities are measured for a month. The results are shown in the box plot.
sattari [20]

Answer:

Interquartile range

Step-by-step explanation:

Range = 32, 29

Median = -6, 3

Upper quatile = 2, 13

Interquartile range = 11, 23

==> Interquartile range has the greatest difference of 23-11 = 12

8 0
2 years ago
Read 2 more answers
Will give brainliest <br> What is the output of y=6x−11 when the input is 5?
MrRissso [65]

Answer:

19

Step-by-step explanation:

y = 6x - 11     If x = 5

y = (6*5) - 11

y = 30 - 11

y = 19

5 0
2 years ago
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