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2 years ago

5(4x+6) simplify and solve

Mathematics

1 answer:

Gemiola [76]2 years ago

8 0

The Answer to the question is 120x

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9. Kevin Durant scored 33 points in a recent game. Here are the outcomes of each

lyudmila [28]

Answer:

Step-by-step explanation:

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2 years ago

Write the following number by entering one digit in each box of the place value chart.

shutvik [7]

Answer:

The number itself is 508.231

Step-by-step explanation:

Any multiplying each of the numbers, we will have the specific places

Hundreds

5 * 100 = 500

Tenths

0 * 10 = 0

ones

8 * 1 = 8

Tenths = 2 * 1/10 = 2/10 = 1/5 = 0.2

Hundredths = 3/100 = 0.03

Thousandths = 1/1000 = 0.001

So we simply sum all these to get the number itself as follows

500 + 8 + 0.2 + 0.03 + 0.001 = 508.231

5 0

2 years ago

Unit 17- calculations

OLEGan [10]

What exactly is your question?

4 0

3 years ago

Read 2 more answers

GIVING BRAINLIEST

bearhunter [10]

Heyo!

l believe the answer is D.

hopefully, this helps you!!!

idqfxemo~

6 0

1 year ago

A tank initially contains 40 ounces of salt mixed in 100 gallons of water. a solution containing 4 oz of salt per gallon is then

stellarik [79]

Let $A(t)$ be the amount of salt in the tank at time $t$ . We're given that $A(0)=40$ . The rate at which this amount changes is given by

$A'(t)=\dfrac{5\text{ gal}}{1\text{ min}}\cdot\dfrac{4\text{ oz}}{1\text{ gal}}-\dfrac{5\text{ gal}}{1\text{ min}}\cdot\dfrac{A(t)\text{ oz}}{100+(5-5)t\text{ gal}}$

$A'(t)+\dfrac{A(t)}{20}=20$

$e^{t/20}A'(t)+e^{t/20}\dfrac{A(t)}{20}=20e^{t/20}$

$\bigg(e^{t/20}A(t)\bigg)'=20e^{t/20}$

$e^{t/20}A(t)=400e^{t/20}+C$

$A(t)=400+Ce^{-t/20}$

Since $A(0)=40$ , we get

$40=400+C\implies C=-360$

so that the amount of salt at time $t$ is

$A(t)=400-360e^{-t/20}$

After 20 minutes, the tank contains

$A(20)=400-360e^{-20/20}\approx267.56\text{ oz}$

6 0

3 years ago