<h3 /><h3>▄▄▄▄▄▄▄▄▄▄▄▄▄▄▄▄▄</h3><h3>Required Solution :</h3>
Let the first even number be 'x' & the second even number be (x + 2)
<u>According to the Question</u>,
⇒x + (x + 2) = 34
⇒x + x + 2 = 34
⇒2x + 2 = 34
⇒2x = 34 - 2
⇒2x = 32
⇒x = 32/2
⇒x = 16
⇒First even number = x = 16
⇒Second even number = (x + 2) = 16 + 2 = 18
<u>∴</u><u> </u><u>The t</u><u>wo consecutive even n</u><u>u</u><u>m</u><u>b</u><u>e</u><u>r</u><u>s</u><u> are 16 & 18</u> ...!
<h3>Verefication : </h3>
As, In our Question it was given that "The sum of two consecutive even numbers is thirty-four". So, as we got our two consecutive even numbers as 16 & 18 ... By this, we can say that these both even numbers should be equals to 34, i.e., 16 + 18 = 34. Hence, The equation which we formed is correct ...!
<h3>▄▄▄▄▄▄▄▄▄▄▄▄▄▄▄▄</h3>
#1 : ( 3 , - 2 )
~~
#2 : ( - 1 , 4 )
~~
I hope that helps you out!!
Any more questions, please feel free to ask me and I will gladly help you out!!
~Zoey
<h3>
Answer: 80 meters</h3>
This is an isosceles triangle. The dashed line is the height which is perpendicular to the base 120. The height is always perpendicular to the base. The dashed line cuts the base into two equal pieces (this only works for isosceles triangles when you cut at the vertex like this).
So we have two smaller triangles each with a base of 60 and a height of x. Focus on one of the right triangles and use the pythagorean theorem to solve for x.
a^2 + b^2 = c^2
x^2 + (60)^2 = (100)^2
x^2 + 3600 = 10000
x^2 = 10000 - 3600
x^2 = 6400
x = sqrt(6400)
x = 80
Each smaller right triangle has side lengths of 60, 80, 100
Note the ratio 60:80:100 reduces to 3:4:5. A 3-4-5 right triangle is a very common pythagorean primitive.
