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alexandr402 [8]
3 years ago
7

1,2,3 or 4? Look at the picture. Thank u!

Mathematics
1 answer:
Georgia [21]3 years ago
7 0

Answer:

option 2

4/7

Step-by-step explanation:

Multiply 4/3x3/7 = 12/21

now simplify  12/21 = 4/7

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10a^{2} b^{2} +6a^{3} b+12a^{3} +2a^{2}

Step-by-step explanation:

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Show that y=2e^(−x) cos(x)−e^(−x) sin(x) is a solution to y''+2y'+2y=0.
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Answer:

y=2e^(−x)cosx−e^(−x)sinx

Satisfies the equation

Step-by-step explanation:

Answer:

y=2e^(−x)cosx−e^(−x)sinx

y = e^(-x)[2cosx - sinx]

Find y' and y" using product law

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4 years ago
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OR:

∵ x² = 8 - (y² -16y + 64) - 2x

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The valve was tested on 270 engines and the mean pressure was 6.6 lbs/square inch. Assume the variance is known to be 0.49. If t
BlackZzzverrR [31]

Answer:

z=\frac{6.6-6.5}{\frac{0.7}{\sqrt{270}}}=2.347      

The p value for this case would be given by"

p_v =2*P(z>2.347)=0.0189  

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Step-by-step explanation:

Information given

\bar X=6.6 represent the sample mean

s=\sqrt{0.49}= 0.7 represent the population deviation

n=270 sample size      

\mu_o =6.5 represent the value that we want to test    

\alpha=0.1 represent the significance level

z would represent the statistic

p_v represent the p value for the test

Hypothesis to verify

We want to verify if the true mean for this case is equal to 6.5 lbs/square inch or not , the system of hypothesis would be:      

Null hypothesis:\mu= 6.5      

Alternative hypothesis:\mu \neq 6.5      

The statistic for this case is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)      

And replacing we got:

z=\frac{6.6-6.5}{\frac{0.7}{\sqrt{270}}}=2.347      

The p value for this case would be given by"

p_v =2*P(z>2.347)=0.0189  

For this case since the p value is higher than the significance level we don't have enough evidence to conclude that the true mean is significantly different from 6.5 lbs/square inch at 10% of significance. So then there is not enough evidence to conclude that the valve does not perform to the specifications

8 0
4 years ago
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