Step 1
Find the area of one equilateral triangle
Applying the law of sines
in this problem
a=b=7 cm
C=60 degrees
so
cm²
Step 2
To calculate the area of the hexagon multiply the area of one equilateral triangle by 
![Area Hexagon=6*[49*\frac{\sqrt{3}}{4}] \\ Area Hexagon=73.5*\sqrt{3}](https://tex.z-dn.net/?f=%20Area%20Hexagon%3D6%2A%5B49%2A%5Cfrac%7B%5Csqrt%7B3%7D%7D%7B4%7D%5D%20%20%5C%5C%20Area%20Hexagon%3D73.5%2A%5Csqrt%7B3%7D%20%20)
cm²
therefore
the answer is the option
73.5 sqrt 3cm²
<h3>
Answer: 1/6</h3>
Work Shown:
x = 0.1666666...
10x = 1.666666...
100x = 16.666666...
100x - 10x = 16.666666... - 1.666666...
90x = 15
x = 15/90
x = (1*15)/(6*15)
x = 1/6
So, 1/6 = 0.1666666...
Answer:
6 to the power of 2.
Step-by-step explanation:
Recall that whenever you divide exponents with the same base, you subtract the powers, but the base will still be the same. Therefore, 6 to the power of 12 divided by 6 to the power of 10 is 6 to the power of 2. Subtract the powers (exponents) or 12 minus 10, and you get 2. Since the base doesn't change, it is still 6. The solution to this expression is 6 to the power of 2. Hope this helps!
Actually, this has little to do with mathematics and geometry but has to do more with logical reasoning. You have two clauses to get a conclusion from. The reasoning is as follows:
Clause 1: <span>Three noncollinear points determine a plane
Clause 2: </span><span>Points S, O, N are noncollinear
</span>Conclusion: Therefore, points S, O and N form a plane.
