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KengaRu [80]
2 years ago
13

Slope I need the slope​

Mathematics
2 answers:
Alexxx [7]2 years ago
5 0

Answer:

slope is 1/20

Step-by-step explanation:

choli [55]2 years ago
4 0
Hi buddy buddy sorry buddy merry merry new buddy merry Christmas buddy buddy
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Which strategy would you choose to expand (x+11)(2x+3) and write an equivalent expression
Vlad1618 [11]

Answer:

Step-by-step explanation:

Given the expression (x+11)(2x+3)

We want to expand it and write equivalent expression

Generally if we want to expand an expression we will take one of the expression in one bracket and multiply with the other bracket and then take the other expression and multiply it with the other

E.g, (a+b) × (c + d)

Then, we take a × (c+d) and also b × (c+d)

We can do it the other way round too and it will give the same results.

So, applying this to the given expression

(x+11)(2x+3)

x(2x+3) + 11(2x+3)

2x² + 3x + 22x + 33

2x² + 25x + 33

Then, the equivalent expression is 2x² + 25x + 33

(x + 11)(2x + 3) = 2x² + 25x + 33

5 0
3 years ago
Solve for x and y.<br> 7x-4<br> #<br> 4y+8<br> 24#<br> +<br> 31
Darina [25.2K]

Answer:

7x-4 = -28

4y+8 = 4(y + 2)

Step-by-step explanation:

3 0
1 year ago
Label the points, lines, and planes to show AB←→ and line j perpendicular to each other in plane R at point A, AB←→ both perpend
algol [13]

Answer:

That would be c

7 0
2 years ago
Read 2 more answers
Tracy recieves payments of $X at the end of each year for n years. The present value of her annuity is 493. Gary receives paymen
vladimir1956 [14]

Answer:

v = 1/(1+i)

PV(T) = x(v + v^2 + ... + v^n) = x(1 - v^n)/i = 493

PV(G) = 3x[v + v^2 + ... + v^(2n)] = 3x[1 - v^(2n)]/i = 2748

PV(G)/PV(T) = 2748/493

{3x[1 - v^(2n)]/i}/{x(1 - v^n)/i} = 2748/493

3[1-v^(2n)]/(1-v^n) = 2748/493

Since v^(2n) = (v^n)^2 then 1 - v^(2n) = (1 - v^n)(1 + v^n)

3(1 + v^n) = 2748/493

1 + v^n = 2748/1479

v^n = 1269/1479 ~ 0.858

Step-by-step explanation:

6 0
3 years ago
where p is the price (in dollars) and x is the number of units (in thousands). Find the average price p on the interval 40 ≤ x ≤
marusya05 [52]

THIS IS THE COMPLETE QUESTION BELOW

The demand equation for a product is p=90000/400+3x where p is the price (in dollars) and x is the number of units (in thousands). Find the average price p on the interval 40 ≤ x ≤ 50.

Answer

$168.27

Step by step Explanation

Given p=90000/400+3x

With the limits of 40 to 50

Then we need the integral in the form below to find the average price

1/(g-d)∫ⁿₐf(x)dx

Where n= 40 and a= 50, then if we substitute p and the limits then we integrate

1/(50-40)∫⁵⁰₄₀(90000/400+3x)

1/10∫⁵⁰₄₀(90000/400+3x)

If we perform some factorization we have

90000/(10)(3)∫3dx/(400+3x)

3000[ln400+3x]₄₀⁵⁰

Then let substitute the upper and lower limits we have

3000[ln400+3(50)]-ln[400+3(40]

30000[ln550-ln520]

3000[6.3099×6.254]

3000[0.056]

=168.27

the average price p on the interval 40 ≤ x ≤ 50 is

=$168.27

8 0
3 years ago
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