Total Weight = Weight of the book + Weight of the CD + Weight of the box
Total Weight = 1 1/4 pound + 1/5 pound + 3/10 pound
Total Weight = 5/4 + 1/5 + 3/10
To add these fractions, you need to put them over a common denominator. To do that, find the least common multiple of 4, 5, and 10. Below is a table of the multiples. The least multiple they have in common is 20, shown in orange. So use 20 as your least common denominator.
1 2 3 4 5 6 7
4 x 4 8 12 16 20 24 ...
5 x 5 10 15 20 25 30 ...
10 x 10 20 30 40 50 60 ...
Can you finish it from here?
Answer:2/3
Step-by-step explanation:
Simplifying
(9m + -6) * 7 = 0
Reorder the terms:
(-6 + 9m) * 7 = 0
Reorder the terms for easier multiplication:
7(-6 + 9m) = 0
(-6 * 7 + 9m * 7) = 0
(-42 + 63m) = 0
Solving
-42 + 63m = 0
Solving for variable 'm'.
Move all terms containing m to the left, all other terms to the right.
Add '42' to each side of the equation.
-42 + 42 + 63m = 0 + 42
Combine like terms: -42 + 42 = 0
0 + 63m = 0 + 42
63m = 0 + 42
Combine like terms: 0 + 42 = 42
63m = 42
Divide each side by '63'.
m = 0.6666666667
Simplifying
m = 0.6666666667=2/3 when simplified
So whenever a problem says "of" a value, multiply.
24 * 1/3 = 24/3 = 8
She saved 8 dollars.
Hope this helps! If you have any questions, just ask!
Answer:
16
Step-by-step explanation:
To solve this, you need to evaluate the function at f(1), which just means that you have to plug in 1 for any x you see in the equation. For example, here f(1) = 2(1) + 2 which simplifies to 4. Next find f(5). By doing the same process you will find that this is 12. The problem asks for f(1) + f(5) so by putting those values in you will get 4+12=16. Hope this helps! :)
EF is tangent to the circle we'll assume; otherwise there's no progress.
Call the center C. ECD is isosceles, formed from two radii and the chord.
Angle CED is complementary to DEF
CED = 90 - 65 = 25 degrees
CDE is congruent, isosceles triangle and all that: CDE=25
That leaves DCE=180-25-25=130 degrees
That's the measure of arc DE as well:
Answer: 130 degrees, choice A
