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3 years ago

Find the 8th term in the geometric sequence 5,-15, 45...

Mathematics

1 answer:

Ratling [72]3 years ago

5 0

Answer: 32805

Step-by-step explanation:

The factor between each term is -3, so you have to multiply -3 eight times (-3 to the power of 8), which is 6561. You have to multiply 6561 by 5 to get the answer.

You might be interested in

Delia measured her bathtub to be 2 meters long. What is an equivalent measurement?

allochka39001 [22]

An equivalent measurement to 2 meters is 200 cm. Since 1 meter is equivalent to 100 cm, multiply both of them by two. So, your answer is - 2 meters is equivalent to 200 cm.

Hope it helps :)

4 0

3 years ago

Solve the equation. 2x + 12 = 2(x + 6)

Vilka [71]

Answer:

Infinitely many solutions

Step-by-step explanation:

Step 1- Distribute into the parenthesis.

2x+12= 2(x+6)

2x+12= (2)x+(2)6

Step 2- Multiply

2x+12= 2x+12

Since they are equal, they are infinite.

5 0

3 years ago

A magazine provided results from a poll of 500500 adults who were asked to identify their favorite pie. Among the 500500 respon

Komok [63]

Answer:

99% confidence interval is wider as compared to the 80% confidence interval.

Step-by-step explanation:

We are given that a magazine provided results from a poll of 500 adults who were asked to identify their favorite pie.

Among the 500 respondents, 14% chose chocolate pie, and the margin of error was given as plus or minus ±3 percentage points.

The pivotal quantity for the confidence interval for the population proportion is given by;

P.Q. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of adults who chose chocolate pie = 14%

n = sample of adults = 500

p = true proportion

Now, the 99% confidence interval for p = $\hat p \pm Z_(_\frac{\alpha}{2}_) \times \sqrt{\frac{\hat p(1-\hat p)}{n} }$

Here, $\alpha$ = 1% so $(\frac{\alpha}{2})$ = 0.5%. So, the critical value of z at 0.5% significance level is 2.5758.

Also, Margin of error = $Z_(_\frac{\alpha}{2}_) \times \sqrt{\frac{\hat p(1-\hat p)}{n} }$ = 0.03 for 99% interval.

So, 99% confidence interval for p = $0.14 \pm2.5758 \times \sqrt{\frac{0.14(1-0.14)}{500} }$

= [0.14 - 0.03 , 0.14 + 0.03]

= [0.11 , 0.17]

Similarly, 80% confidence interval for p = $0.14 \pm 1.2816 \times \sqrt{\frac{0.14(1-0.14)}{500} }$

Here, $\alpha$ = 20% so $(\frac{\alpha}{2})$ = 10%. So, the critical value of z at 10% significance level is 1.2816.

Also, Margin of error = $Z_(_\frac{\alpha}{2}_) \times \sqrt{\frac{\hat p(1-\hat p)}{n} }$ = 0.02 for 80% interval.

So, 80% confidence interval for p = [0.14 - 0.02 , 0.14 + 0.02]

= [0.12 , 0.16]

Now, as we can clearly see that 99% confidence interval is wider as compared to 80% confidence interval. This is because more the confidence level wider is the confidence interval and we are more confident about true population parameter.

5 0

3 years ago

A gardener found that he was able to plant 1/4 of a packet of flower seeds in 1/5 of a garden.At this rate how much of the garde

telo118 [61]

Answer: $\frac{4}{5}$ of garden.