4 years ago

HELP! I NEED HELP WITH MATH IMAGE ATTACHED

Mathematics

1 answer:

bixtya [17]4 years ago

3 0

1. Adjacent angles have <em>a common side + vertex</em>.

2. Vertical angles are opposite sides of each other, and have <em>two common sides and one vertex</em>.

So,

13. Adjacent: they share a side + vertex.

14. Vertical: they are opposite to each other with the same two lines.

15. Neither: they do not share any sides or vertex.

16. Adjacent: they share a side + vertex.

You might be interested in

Factor completely x^3-8x^2-2x+16=

Contact [7]

Answer:

(x-8)(x^2-2)

Step-by-step explanation:

take x common from the first 2 terms and take -2 common from the last two terms. Then, take (x-8) common.

x^2(x-8)-2(x-8) = (x-8)(x^2-2)

4 0

3 years ago

Elizabeth went to the candy store and wanted to use the dimensional analysis she had learned in class that day. She only had a c

andrew-mc [135]

Answer: 315,392

Step-by-step explanation: this took me some time but I multiplied multiple times each time and I got this I hope it’s correct.

Btw I multiplied 2 times 8 then multipled with 11 then multipied 172 times 8 then multiplied by 14 and got 19,712. Then, I multiplied 19,712 by 16 and got 315,392

I had to edit cause I miscalculated :/ anyways I hope this is correct

6 0

3 years ago

Please help me with this question. Question C (i) and (ii)

GenaCL600 [577]

Answer:

idk

hahahahahaha

Step-by-step explanation:

8 0

3 years ago

Tramain made the table below for the system of equations y=2x+1 and y=-3x+11

frosja888 [35]

Boy that math stuff will kill a cracker

5 0

3 years ago

6x+5=29 what is the answer help me

Contact [7]

$6x+5=29$

$6x=24$ $:$ $subtract$ $5$ $from$ $both$ $sides$

$x = \frac{24}{6}$ $:$ $divide$ $both$ $sides$ $by$ $6$

$x=4$

7 0

3 years ago