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dalvyx [7]
1 year ago
8

Suppose sin(A) = 1/4. use the trig identity sin^2(A)+cos^2(A)=1 to find cos(A) in quadrant II. around to ten-thousandth.

Mathematics
1 answer:
larisa86 [58]1 year ago
8 0

In quadrant II, \cos(A) will be negative. So

\sin^2(A) + \cos^2(A) = 1 \implies \cos(A) = -\sqrt{1 - \sin^2(A)} = -\dfrac{\sqrt{15}}4 \approx \boxed{-0.9682}

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[See Below]

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\boxed{Hey~There!}

__________________________________________________________

\boxed{Solve~-3x

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\boxed{The~answer~is: x > -3}

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