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arsen [322]
4 years ago
15

How, do you divide big numbers.

Mathematics
2 answers:
Triss [41]4 years ago
7 0

Answer:

hope this helps!   :)

Step-by-step explanation:

Partition the primary number of the profit (or the two first numbers if the past advance took another digit) by the principal digit of the divisor. Compose the consequence of this division in the space of the remainder. Increase the digit of the remainder by the divisor, compose the outcome underneath the profit and deduct it

Rus_ich [418]4 years ago
3 0

Answer:

divide them by 2 or other numbers

Step-by-step explanation:

hope this helps

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Given that k(x) = (2x + 4)2
taurus [48]

Answer:

f(x)=4x\\g(x)=x+2

Step-by-step explanation:

Because we have to rewrite this equation in the format f(g(x)), we have to divide, or factor to find basic terms,

Expanding the value of k(x), we have k(x)=4x+8. We see that each term can be divisible by 4, so we can factor out 4 to get

k(x)=4(x+2)

Now, we have two different terms getting multiplied. We can separate the two to get 4 \text{ and} (x+2)

Because we are multiplying 4 by the other term, this is represented by 4x

Now, we can just set f(x) and g(x) to these functions:

f(x)=4x\\g(x)=x+2

Now, just to make sure, we can plug a value into k(x) and the same value into f(g(x)). Plugging in 1, we have (2(1)+4)2 as 2(2+4), which is 2(6) = 12.

Plugging 1 into f(g(x)), we can evaluate g(1) first, to get 1 + 2 = 3. Now, f(3) = 4(3)= 12, which is the same for k(x).

3 0
3 years ago
How do I do this????
castortr0y [4]

Answer:

5.41

Step-by-step explanation:

4 0
3 years ago
How do I complete these questions a bit confused . (extra credit work )​
otez555 [7]

Answer:

(1)

a = \frac{3\sqrt 3}{2}

b = \frac{3}{2}

(2)

a = \sqrt 6

b = \sqrt 2

Step-by-step explanation:

Solving (1):

Considering

\theta = 60^o

We have:

\sin(\theta) = \frac{Opposite}{Hypotenuse}

This gives:

\sin(60^o) = \frac{a}{3}

Solve for a

a = 3 * \sin(60^o)

\sin(60^o) = \frac{\sqrt 3}{2}

So:

a = 3 * \frac{\sqrt 3}{2}

a = \frac{3\sqrt 3}{2}

To solve for b, we make use of Pythagoras theorem

3^2 = a^2 + b^2

This gives

3^2 = (\frac{3\sqrt 3}{2})^2 + b^2

9 = \frac{9*3}{4} + b^2

9 = \frac{27}{4} + b^2

Collect like terms

b^2 = 9 - \frac{27}{4}

Take LCM and solve

b^2 = \frac{36 - 27}{4}

b^2 = \frac{9}{4}

Take square roots

b = \frac{3}{2}

Solving (2):

Considering

\theta = 60^o

We have:

\sin(\theta) = \frac{Opposite}{Hypotenuse}

This gives:

\sin(60^o) = \frac{a}{2\sqrt 2}

Solve for a

a = 2\sqrt 2 * \sin(60^o)

\sin(60^o) = \frac{\sqrt 3}{2}

So:

a = 2\sqrt 2 * \frac{\sqrt 3}{2}

a = \sqrt 2 * \sqrt 3

a = \sqrt 6

To solve for b, we make use of Pythagoras theorem

(2\sqrt 2)^2 = a^2 + b^2

This gives

(2\sqrt 2)^2 = (\sqrt 6)^2 + b^2

8 = 6 + b^2

Collect like terms

b^2 = 8 - 6

b^2 = 2

Take square roots

b = \sqrt 2

3 0
3 years ago
How many sixths does it take to make the same amount of 1/3
Elena L [17]
It takes 2/6 (two sixths) to make 1/3.
5 0
4 years ago
Read 2 more answers
What are the x and y intercepts
Fynjy0 [20]
It’s called the origin.
7 0
3 years ago
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