Answer: The correct statements are
The GCF of the coefficients is correct.
The variable c is not common to all terms, so a power of c should not have been factored out.
David applied the distributive property.
Step-by-step explanation:
GCF = Greatest common factor
1) GCF of coefficients : (80,32,48)
80 = 2 × 2 × 2 × 2 × 5
32 = 2 × 2 × 2 × 2 × 2
48 = 2 × 2 × 2 × 2 × 3
GCF of coefficients : (80,32,48) is 16.
2) GCF of variables :(
)
= b × b × b × b
= b × b
=b × b × b × b
GCF of variables :(
) is ![b^2](https://tex.z-dn.net/?f=b%5E2)
3) GCF of
and c: c is not the GCF of the polynomial. The variable c is not common to all terms, so a power of c should not have been factored out.
4) ![80b^4-32b^2c^3+48b^4c](https://tex.z-dn.net/?f=80b%5E4-32b%5E2c%5E3%2B48b%5E4c)
David applied the distributive property.
20 + 4 + 3/10 + 5/100 + 7/1000
Answer: ![\mu=2.88\ \&\ \sigma^2=0.115](https://tex.z-dn.net/?f=%5Cmu%3D2.88%5C%20%5C%26%5C%20%5Csigma%5E2%3D0.115)
Step-by-step explanation:
Given : The probability of a correct classification of any part is : p=0.96
sample size : n= 3
The formula to find the mean and variance for binomial distribution is given by :-
![\mu=np\\\\\sigma^2=np(1-p)](https://tex.z-dn.net/?f=%5Cmu%3Dnp%5C%5C%5C%5C%5Csigma%5E2%3Dnp%281-p%29)
Let the random variable X denote the number of parts that are correctly classified.
The, for the given situation, we have
![\mu=3(0.96)=2.88\\\\\sigma^2=(3)(0.96)(1-0.96)=0.1152\approx0.115](https://tex.z-dn.net/?f=%5Cmu%3D3%280.96%29%3D2.88%5C%5C%5C%5C%5Csigma%5E2%3D%283%29%280.96%29%281-0.96%29%3D0.1152%5Capprox0.115)
Hence, the mean and variance of X are 2.88 and 0.115 respectively.
There are two negative roots to the provided polynomial function
f(x) = x⁷ – 2x⁴ + 7x² + 2x – 2
<h3>What is polynomial?</h3>
Polynomial is the combination of variables and constants systematically with "n" number of power in ascending or descending order.
![\rm a_1x+a_2x^2+a_3x^3+a_4x^4..........a_nx^n](https://tex.z-dn.net/?f=%5Crm%20a_1x%2Ba_2x%5E2%2Ba_3x%5E3%2Ba_4x%5E4..........a_nx%5En)
We have a polynomial function:
f(x) = x⁷ – 2x⁴ + 7x² + 2x – 2
![\rm f(x) =\left(x+1\right)\left(x^6-x^5+x^4-3x^3+3x^2+4x-2\right)](https://tex.z-dn.net/?f=%5Crm%20f%28x%29%20%3D%5Cleft%28x%2B1%5Cright%29%5Cleft%28x%5E6-x%5E5%2Bx%5E4-3x%5E3%2B3x%5E2%2B4x-2%5Cright%29)
Using the zero product property:
![\rm \left x+1\right = 0 \ \ \ or \left x^6-x^5+x^4-3x^3+3x^2+4x-2\right = 0](https://tex.z-dn.net/?f=%5Crm%20%5Cleft%20x%2B1%5Cright%20%3D%200%20%5C%20%5C%20%5C%20or%20%5Cleft%20x%5E6-x%5E5%2Bx%5E4-3x%5E3%2B3x%5E2%2B4x-2%5Cright%20%3D%200)
After solving:
x = -1, x = -0.853, and x = 0.418 (using the graph method)
Thus, there are two negative roots to the provided polynomial function
f(x) = x⁷ – 2x⁴ + 7x² + 2x – 2
Learn more about Polynomial here:
brainly.com/question/17822016
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Answer:
1 6/8
Step-by-step explanation:
add 1/8 to 5/8 by adding just the numerators
1 + 5 = 6
now you have 6/8. add the 1 and you have 1 6/8
hope this helped, have a good day :)