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eimsori [14]
3 years ago
15

Find the number of 4-digit numbers that contain b at least three odd digits.

Mathematics
1 answer:
melamori03 [73]3 years ago
6 0

Answer:

  3000

Step-by-step explanation:

There are 5 odd digits, so 5^3 = 125 ways to have 3 odd digits.

Given 3 odd digits, the first digit can be even, but not zero, so there are 4 ways to do that.

The second, third, or fourth digits can be even 5 ways, so there are ...

  125(4 +5 +5 +5) = 2375

ways to have 3 odd digits in a 4-digit number.

__

There are 5^4 = 625 ways to have 4 odd digits.

The number of 4-digit numbers with 3 or 4 odd digits is ...

  2375 +625 = 3000

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Well formatted version of the question can be found in the picture attached below :

Answer:

Both Carlos and Irene

Step-by-step explanation:

Given the expression (28x - 8)

Carlos : 2(14x - 4)

Danny : 7(4x - 1)

Irene : 4(7x - 2)

The factored expression Given by Carlos, Irene and Danny can be expanded to check if it gives the same expression as that Given in the question :

Carlos :

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Danny :

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From.the expanded solutions obtained ;

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

<u>Given points</u>

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Answer:

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