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natali 33 [55]
3 years ago
11

The equation above can be used to calculate the volume V, of a sphere with radius r. If the volume of a sphere is 288πcm3, what

is the radius of the sphere in centimeters? Select one: A. 13 B. 9 C. 16 D. 6
Mathematics
1 answer:
mylen [45]3 years ago
7 0

Answer:

Step-by-step explanation:

V=4/3πr^3

288πcm^3=4/3πr^3

288×3πcm^3=4/3πr^3

864πcm^3=4πr^3

r^3=216

r=6cm

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Find the equation of the tangent line to the curve (a lemniscate)
olya-2409 [2.1K]

Answer:

m=\frac{9}{13} and b=\frac{40}{13}

Step-by-step explanation:

The equation of curve is

2(x^2+y^2)^2=25(x^2-y^2)

We need to find the equation of the tangent line to the curve at the point (-3, 1).

Differentiate with respect to x.

2[2(x^2+y^2)\frac{d}{dx}(x^2+y^2)]=25(2x-2y\frac{dy}{dx})

4(x^2+y^2)(2x+2y\frac{dy}{dx})=25(2x-2y\frac{dy}{dx})

The point of tangency is (-3,1). It means the slope of tangent is \frac{dy}{dx}_{(-3,1)}.

Substitute x=-3 and y=1 in the above equation.

4((-3)^2+(1)^2)(2(-3)+2(1)\frac{dy}{dx})=25(2(-3)-2(1)\frac{dy}{dx})

40(-6+2\frac{dy}{dx})=25(-6-2\frac{dy}{dx})

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80\frac{dy}{dx}+50\frac{dy}{dx}=-150+240

130\frac{dy}{dx}=90

Divide both sides by 130.

\frac{dy}{dx}=\frac{9}{13}

If a line passes through a points (x_1,y_1) with slope m, then the point slope form of the line is

y-y_1=m(x-x_1)

The slope of tangent line is \frac{9}{13} and it passes through the point (-3,1). So, the equation of tangent is

y-1=\frac{9}{13}(x-(-3))

y-1=\frac{9}{13}(x)+\frac{27}{13}

Add 1 on both sides.

y=\frac{9}{13}(x)+\frac{27}{13}+1

y=\frac{9}{13}(x)+\frac{40}{13}

Therefore, m=\frac{9}{13} and b=\frac{40}{13}.

5 0
3 years ago
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Hello!

7d + 12 -4d -3\\

Explanation:

↓↓↓↓↓↓↓↓↓↓↓

First this problem it should be the group like terms.

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Then you add similar elements.

7d-4d=3d

3d+12-3

You can also add or subtract by the numbers.

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Answer⇒⇒⇒3d+9

Hope this helps!

Thank you for posting your question at here on Brainly.

Have a great day!

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