3 years ago

Please write the equation

Mathematics

1 answer:

Ksenya-84 [330]3 years ago

3 0

the equation is 21 * 5 - 5 and that shall equal ur answer

You might be interested in

Complete the equation for this model.

Arturiano [62]

Answer:

(-18) + (-2) = -20

Step-by-step explanation:

arrow is moving from -18 to -20.

3 0

1 year ago

Find the maximum and minimum values of the function f(x,y)=2x2+3y2−4x−5 on the domain x2+y2≤100. The maximum value of f(x,y) is:

ryzh [129]

First find the critical points of f :

$f(x,y)=2x^2+3y^2-4x-5=2(x-1)^2+3y^2-7$

$\dfrac{\partial f}{\partial x}=2(x-1)=0\implies x=1$

$\dfrac{\partial f}{\partial y}=6y=0\implies y=0$

so the point (1, 0) is the only critical point, at which we have

$f(1,0)=-7$

Next check for critical points along the boundary, which can be found by converting to polar coordinates:

$f(x,y)=f(10\cos t,10\sin t)=g(t)=295-40\cos t-100\cos^2t$

Find the critical points of g :

$\dfrac{\mathrm dg}{\mathrm dt}=40\sin t+200\sin t\cos t=40\sin t(1+5\cos t)=0$

$\implies\sin t=0\text{ OR }1+5\cos t=0$

$\implies t=n\pi\text{ OR }t=\cos^{-1}\left(-\dfrac15\right)+2n\pi\text{ OR }t=-\cos^{-1}\left(-\dfrac15\right)+2n\pi$

where n is any integer. We get 4 critical points in the interval [0, 2π) at

$t=0\implies f(10,0)=155$

$t=\cos^{-1}\left(-\dfrac15\right)\implies f(-2,4\sqrt6)=299$

$t=\pi\implies f(-10,0)=235$

$t=2\pi-\cos^{-1}\left(-\dfrac15\right)\implies f(-2,-4\sqrt6)=299$

So f has a minimum of -7 and a maximum of 299.

4 0

3 years ago

The length of a rectangle is 24 units. Can the perimeter x of the rectangle be 60 units when its width y is 11 units? (1 point)

zlopas [31]

The first choice is correct. No, the rectangle cannot have x=60 and y=11 because x=48+2y.

Perimeter is x=2w+2y. Therefore x=2(24)+2(11) which equals 70 not 60.

7 0

3 years ago

What is the y-coordinate of point T? Write a decimal coordinate.

Eva8 [605]

Where is the point t in question

8 0

3 years ago

Read 2 more answers

In football, the goal posts in the end zone are 7.11 meters apart.how many centimeters are in 7.11

aev [14]

Move the decimal right 3 times

4 0

2 years ago