2 years ago

A fish population in a lake decreases by 2% each year. What is the common ratio? (Write your answer as a decimal)

Mathematics

1 answer:

galina1969 [7]2 years ago

8 0

Answer:

the common ratio is 0.98.

Step-by-step explanation:

A fish population in a lake decreases by 2% each year. We are asked to find the common ratio.

The decrease of population of fish 2% annually means the population becomes next year 100% - 2% = 98%

Therefore, the common ratio would be 98%. Upon converting 98 percent to a decimal we will get,

98% = $\frac{98}{100}=0.98$

Therefore, the common ratio or decay factor is 0.98.

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A sphere has a volume of V=900 in cubed. What is the surface area?

ycow [4]

First, we must solve for the radius of the sphere:
V= $\frac{4}{3}$ $\pi$ $r^{3}$
r=(3 $\frac{V}{4 \pi }$ ) $^{ \frac{1}{3} }$
r=(3* $\frac{900}{4 \pi }$ ) $^{ \frac{1}{3} }$
r≈5.99

Second, we must solve for surface area:
A=4 $\pi$ $r^{2}$
A=4* $\pi$ * $5.99^{2}$
A≈450.88 $in^{2}$