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3 years ago

78(−32−48x)+36=23(−33x−18)−10x Solve for x.

Mathematics

2 answers:

Nat2105 [25]3 years ago

8 0

I believe the answer is 6 because if you use process of elmination it comes out to be 6 hopfully it helps

Blizzard [7]3 years ago

5 0

Answer: The required solution is x = -0.69.

Step-by-step explanation: We are given to solve the following equation for the value of x :

$78(-32-48x)+36=23(-33x-18)-10x~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)$

To find the value of x, we must bring all the terms involving x on one side of the equality.

The solution of equation (i) is as follows:

$78(-32-48x)+36=23(-33x-18)-10x\\\\\Rightarrow -2496-3744x+36=-759x-414-10x\\\\\Rightarrow -3744x-2460=-769x-414\\\\\Rightarrow -3744x+769x=-414+2460\\\\\Rightarrow -2975x=2046\\\\\Rightarrow x=-\dfrac{2046}{2975}\\\\\Rightarrow x=-0.69.$

Thus, the required solution is x = -0.69.

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At a fabric store, fabrics are sold by the yard. A dressmaker spent $36.35 on 4.25 yards of silk and cotton fabrics for a dress.

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Given:

The system of equations that represent the constraints for the given situation is

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We have,

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Multiply equation (i) by 4.

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Subtracting (iii) from (ii), we get

$16.90x+4y-(4x+4y)=36.35-17$

$16.90x+4y-4x-4y=19.35$

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Put this value in (i).

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$y=4.25-1.5$

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3 years ago

The number of accidents per week at a hazardous intersection varies with mean 2.2 and standard deviation 1.1. This distribution

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Answer:

Step-by-step explanation:

Hello!

The definition of the Central Limi Theorem states that:

Be a population with probability function f(X;μ,δ²) from which a random sample of size n is selected. Then the distribution of the sample mean tends to the normal distribution with mean μ and variance δ²/n when the sample size tends to infinity.

As a rule, a sample of size greater than or equal to 30 is considered sufficient to apply the theorem and use the approximation.

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If the variable of interest is X: the number of accidents per week at a hazardous intersection.

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