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maxonik [38]
3 years ago
12

Find the value of x using angle properties & the measure of

Mathematics
1 answer:
Jobisdone [24]3 years ago
8 0

Answer:

15.

x = 20

16.

\angle BFH = 100\textdegree

\angle CBD = 100\textdegree (if needed)

-------------------------------------------------------------------

17.

x = 7

18.

\angle BFH = 68\textdegree

Step-by-step explanation:

15. The two following angles, which is \angle CBD and \angle BFH, are <u>Corresponding Angles</u>. Write an expression by using the following measurements from  \angle CBD and  \angle BFH. Then, solve the expression for the value of x:

\angle CBD = 5x

\angle BFH = 3x + 40

5x = 3x + 40

Solve for x:

5x = 3x + 40

5x - 3x = 3x - 3x + 40

2x = 40

\frac{2x}{2} = \frac{40}{2}

x = 20

16. After you have the value x use it to find the <u>actual</u> measurements of both \angle CBD and \angle BFH, by applying x to the following expressions from both \angle CBD and \angle BFH and solve them:

-The value of x:

x = 20

-Solve for \angle CBD:

\angle CBD = 5x

5(20)

100

-The <u>actual</u> measurement of \angle CBD:

\angle CBD = 100\textdegree

-Solve for \angle BFH:

\angle BFH = 3x + 40

3(20) + 40

60 + 40

100

-The <u>actual</u> measurement of \angle BFH: (if needed)

\angle BFH = 100\textdegree

----------------------------------------------------------------------------

17. The two following angles, which is \angle BFE and \angle DBF are <u>Alternate Interior Angles</u> .Write an expression by using the following measurements from \angle BFE and \angle DBF. Then, solve the expression for the value of x:

\angle BFE = 16x

\angle DBF = 4x + 84

16x = 4x + 84

-Solve for x:

16x = 4x + 84

16x - 4x = 4x - 4x + 84

12x = 84

\frac{12x}{12} = \frac{84}{12}

x = 7

18. After you have the value x use it to find the <u>actual</u> measurement of  \angle DBF, by applying x to the expression from \angle DBF and solve it and find the actual measurement of an angle that is not labeled, which is \angle BFH:

-The value of x:

x = 7

Solve for \angle DBF:

\angle DBF = 4x + 84

4(7) + 84

28 + 84

112

-The <u>actual</u> measurement of \angle DBF:

\angle DBF = 112\textdegree

-Since both \angle DBF and \angle BFH are supplementary (two angles that equals to 180\textdegree), and you want to find the <u>actual</u> measurement of \angle BFH, Use the measurement of \angle DBF and subtract it from 180\textdegree:

\angle DBF - 180\textdegree

112\textdegree - 180\textdegree = 68\textdegree

-The <u>actual</u> measurement of \angle BFH:

\angle BFH = 68\textdegree

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3 years ago
HELP BRAINLIEST FOR. CORRECT AND ALL ANSWERED ANSWER
SpyIntel [72]

Answer:

1. 6/7

2. 1/2

3. 7/10

4. 39/40

5. 15/28

6. 3/10

7. 7/12

8. 1/6

9. 5/12

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 Step-by-step explanation:

7 0
3 years ago
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Please someone help me solve this i dpnt know the answer​
kozerog [31]
<h2><u>Answer With Explanation:</u></h2>

<u>Firstly, let's start with <XOZ: =55°</u>

We know that <ZOQ is 70° and angles on a line add up to 180° so we do 180-70=110 110 divided by 2 = 55 so the 2 angles (XOZ & XOP are 55)

<u>Secondly, <OMN, <MON & <ONM = All are 60°</u>

These 2 angles are joined to create an equilateral triangle which always adds up to 180°

So, there are 3 points to this triangle, therefore we divide 180 by 3 which is 60. The angles are 60°

<u>Thirdly, <QON: =55°</u>

This angle lies on the line XON which needs to add up to 180°

As we worked out before, <XOZ was 55°

So, <ZOQ was already given as 70°

We then do 55+70=125 then 180-125=55°

<QON is 55°

(I'm only in Grade 9 LOL)

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