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3 years ago

Please help!!!!CE is tangent to this circle, CD is a radius and ECB=48 what is BAC

Mathematics

1 answer:

den301095 [7]3 years ago

4 0

Answer:

48degrees

Step-by-step explanation:

From the circle geometry shown, traingle BDC is an isosceles triangle which shows means that their base angels are the same. Hence;

<B = <C

<CBD + <BCD + <D = 180

<BCD + <BCD + <D =180

2<BCD + <BDC = 180

Get <BCD;

<BCD+ <ECB = 90

<BCD + 48 = 90

<BCD = 90 - 48

<BCD = 42degrees

Get <BDC

2<BCD + <BDC = 180

2(42)+ <BDC = 180

84 + <BDC = 180

<BDC = 180 - 84

<BDC = 96

Since angle at the centre is twice that at the circumference, then;

<BAC = 1/2(<BDC )

<BAC = 96/2

<BAC = 48degrees

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Find the period of the function. y=3 sin x/8

Alexus [3.1K]

Answer:

The period of given function is $Period = 16\pi$

So, Option B is correct.

Step-by-step explanation:

In this question we need to find the period of the function y= 3 sin x/8

The formula used to find period of function is: $\frac{2\pi }{b}$

We need to know the value of b.

To find the value of b we compare the standard equation with the equation of function given.

Standard Equation: y = a sin(bx - c) +d

Given Equation: y= 3 sin(x/8)

Comparing we get:

a= 3

b= 1/8

c= 0

d=0

So, we get the value of b i.e 1/8. Putting it in the formula to find period of given function.

$Period = \frac{2\pi }{b}$

$Period = \frac{2\pi }{\frac{1}{8}}$

Solving,

$Period = 2\pi *8$

$Period = 16\pi$

So, the period of given function is $Period = 16\pi$

5 0

3 years ago

Tara wants to fix the location of a mountain by taking measurements from two positions 3 miles apart. From the first position, t

Black_prince [1.1K]

Answer:

Shortest distance from the mountain is 3.17 miles.

Step-by-step explanation:

From the figure attached,

Let a mountain is located at point A.

Angle between the mountain and point B (∠B) = 53°

Angle between the mountain and point C (∠C) = 78°

Distance between these points = 3 miles

Since, m∠A + m∠B + m∠C = 180°

m∠A + 53° + 78° = 180°

m∠A = 180°- 131° = 49°

By applying sine rule in triangle ABC,

$\frac{\text{sin}(49)}{BC}=\frac{\text{sin}(53)}{AC}= \frac{\text{sin}(78)}{AB}$

$\frac{\text{sin}(49)}{3}=\frac{\text{sin}(53)}{AC}= \frac{\text{sin}(78)}{AB}$

$\frac{\text{sin}(49)}{3}=\frac{\text{sin}(53)}{AC}$

AC = $\frac{3\text{sin}(53)}{\text{sin}(49)}$

AC = 3.17 miles

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AB = $\frac{3\text{sin}(78)}{\text{sin}(49)}$

AB = 3.89 miles

Therefore, shortest distance from the mountain is 3.17 miles.

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2 years ago

The value of y varies directly with x, and y = 18 when x = 12. find y when x = 132.

sveta [45]

This would be 198 because 12 times 1.5 equals 18 so when you multiply 132 by 1.5 you get 198

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3 years ago

Arturiano [62]

Correct me if I’m wrong but I’d go with
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3 years ago

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2 years ago

Please help!!!!CE is tangent to this circle, CD is a radius and ECB=48 what is BAC​

Please help!!!!CE is tangent to this circle, CD is a radius and ECB=48 what is BAC