9514 1404 393
Answer:
x = 10·cos(θ) -4·cot(θ)
Step-by-step explanation:
Apparently, we are to assume that the horizontal lines are parallel to each other.
The relevant trig relations are ...
Sin = Opposite/Hypotenuse
Cos = Adjacent/Hypotenuse
If the junction point in the middle of AB is labeled X, then we have ...
sin(θ) = 4/BX ⇒ BX = 4/sin(θ)
cos(θ) = x/XA ⇒ XA = x/cos(θ)
Then ...
BX +XA = AB = 10
Substituting for BX and XA using the above relations, we get
4/sin(θ) +x/cos(θ) = 10
Solving for x gives ...
x = (10 -4/sin(θ))·cos(θ)
x = 10·cos(θ) -4·cot(θ) . . . . . simplify
_____
We used the identity ...
cot(θ) = cos(θ)/sin(θ)
Two angles are supplementary when they <span>add up to 180 degrees.
x = angle
19x-60 = </span><span>supplement angle
x + 19x - 60 = 180
20x = 180 + 60
20x = 240
x = 240/20
x = 12</span>° ← answer
XYA = (104 -52)/2
52 /2 = 26
the answer is 26 degrees
Answer:
15/8
Step-by-step explanation:
Opp/Adj of angle x means Tan x
that would be 15/8
For an explicit formula in its simplified form, we must evaluate the first two terms.
For
,
, and
. We see that the common difference is
, and
, so we write,
.
The correct answer is
B.
