All categories

3 years ago

Twenty more than the number n is 125. What is the value of n? 145 125 105 20

Mathematics

2 answers:

DENIUS [597]3 years ago

7 0

Answer:

105

Step-by-step explanation:

twenty more that the number n is 125 so n+20=125
subtract twenty on both sides
125–20=n
125–20=105
n=105

The wording is really word but I'm pretty sure this is correct

sweet-ann [11.9K]3 years ago

6 0

Answer:

105

Step-by-step explanation:

n=105 as 20 more than 105 is 125. Hope it helps!

You might be interested in

Please help<br> 80 POINTS plus BRAINLIEST, THANKS AND 5 STAR

Molodets [167]

Answer:

Steps and solution in the attached picture.

Step-by-step explanation:

Steps and solution in the attached picture.

3 0

2 years ago

Could someone explain to me what is the process

Phoenix [80]

Answer:

You just multiple the number of apples one truck can carry by the number of trucks total.

The second one you divide 4551 by 37 and round your answer up.

Step-by-step explanation:

So it would be 23*37.

3 0

3 years ago

Read 2 more answers

A property is listed for $580,000. The listing agreement promises to

IgorC [24]

Answer:

$26,096

Step-by-step explanation:

property taxes = 31 January + 28 February + 31 March + 30 April + 31 May + 4 June = 155 days

property taxes = (155 days/365 days) x $5,309 = $2,254

agent's commission = 7% x $547,000 = $38,290

seller's net = $547,000 - $480,000 (mortgage) - $38,290 (agent's commission) - $360 (home warranty) - $2,254 (property taxes) = $26,096

8 0

3 years ago

1. Express <img src="https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bx%282x%2B3%29%20%7D" id="TexFormula1" title="\frac{1}{x(2x+3) }" a

katovenus [111]

1. Let a and b be coefficients such that

$\dfrac1{x(2x+3)} = \dfrac ax + \dfrac b{2x+3}$

Combining the fractions on the right gives

$\dfrac1{x(2x+3)} = \dfrac{a(2x+3) + bx}{x(2x+3)}$

$\implies 1 = (2a+b)x + 3a$

$\implies \begin{cases}3a=1 \\ 2a+b=0\end{cases} \implies a=\dfrac13, b = -\dfrac23$

so that

$\dfrac1{x(2x+3)} = \boxed{\dfrac13 \left(\dfrac1x - \dfrac2{2x+3}\right)}$

2. a. The given ODE is separable as

$x(2x+3) \dfrac{dy}dx} = y \implies \dfrac{dy}y = \dfrac{dx}{x(2x+3)}$

Using the result of part (1), integrating both sides gives

$\ln|y| = \dfrac13 \left(\ln|x| - \ln|2x+3|\right) + C$

Given that y = 1 when x = 1, we find

$\ln|1| = \dfrac13 \left(\ln|1| - \ln|5|\right) + C \implies C = \dfrac13\ln(5)$

so the particular solution to the ODE is

$\ln|y| = \dfrac13 \left(\ln|x| - \ln|2x+3|\right) + \dfrac13\ln(5)$

We can solve this explicitly for y :

$\ln|y| = \dfrac13 \left(\ln|x| - \ln|2x+3| + \ln(5)\right)$

$\ln|y| = \dfrac13 \ln\left|\dfrac{5x}{2x+3}\right|$

$\ln|y| = \ln\left|\sqrt[3]{\dfrac{5x}{2x+3}}\right|$

$\boxed{y = \sqrt[3]{\dfrac{5x}{2x+3}}}$

2. b. When x = 9, we get

$y = \sqrt[3]{\dfrac{45}{21}} = \sqrt[3]{\dfrac{15}7} \approx \boxed{1.29}$

8 0

2 years ago

Which statement about the equation is true?

Papessa [141]

The equation has no solution

8 0

3 years ago

Read 2 more answers