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DaniilM [7]
3 years ago
6

Multiply 2x(x^2 + 5)

Mathematics
1 answer:
Helen [10]3 years ago
6 0
2x^3 + 10x (you distribute 2x to x^2 and 5)
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Solve the equation 0.25 (8z - 4) = z + 8 - 2z
Andrew [12]
Distribute
2z-1=z+8-2z
add like terms
2z-1=-z+8
add z to both sides
3z-1=8
add 1 to both sides
3z=9
divide both sides by 3
z=3
4 0
3 years ago
Read 2 more answers
If f(x) = x2 - 1 and g(x) = 2x - 3, what is the domain of (fog)(x)?
ladessa [460]

Answer:

domain will be ( -∞, ∞)

Step-by-step explanation:

The given functions are f(x) = x² - 1 and g(x) = 2x - 3

We have to find domain of (fog)(x)

We will find the function (fg)(x) first.

(fog)(x) = f[g(x)]

         = (2x - 3)²

         = 4x² + 9 - 12x - 1

        = 4x² - 12x + 8

       = 4 (x² - 3x + 2)

The given function is defined for all values of x.

Therefore, domain will be ( -∞, ∞)

<u>brainly.com/question/2458431</u>

4 0
2 years ago
PLEASE HELP ME!!
Ludmilka [50]

Answer:

<h2>The population will reach 1200 after about 2.8 years</h2>

Step-by-step explanation:

The question is incomplete. Here is the complete question.

The population of a certain species of bird in a region after t years can be modeled by the function P(t) = 1620/ 1+1.15e-0.42t , where t ≥ 0. When will the population reach 1,200?

According to question we are to calculate the time t that the population P(t) will reach 1200.To do this we will substitute P(t) = 1,200 into the equation and calculate for the time 't'.

Given;

P(t) = \frac{1620}{1+1.15e^{-0.42t} } \\\\at \ P(t)= 1200;\\\\1200 =  \frac{1620}{1+1.15e^{-0.42t} }\\\\cross\ multiplying\\\\1+1.15e^{-0.42t} = \frac{1620}{1200} \\\\1+1.15e^{-0.42t}  = 1.35\\\\1.15e^{-0.42t} = 1.35-1\\\\e^{-0.42t} = \frac{0.35}{1.15}\\ \\e^{-0.42t}  = 0.3043\\\\Taking \ ln\ of\ both\ sides\\\\lne^{-0.42t}  = ln0.3043\\\\-0.42t = -1.1897\\\\t = \frac{-1.1897}{-0.42} \\\\t = 2.8 years\\\\

The population will reach 1200 after about 2.8 years

6 0
3 years ago
What is 6,000,000 divided by 2
Alenkasestr [34]

Answer:

3,000,000

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
How to solve a quadratic equation that does not factor?
svlad2 [7]
Use the formula or complete the square.
The zeroes of the quadratic can be real and rational; real and irrational; complex conjugates.
If the quadratic is ax²+bx+c, x=(-b+√b²-4ac)/2a.
If b² > 4ac the solutions are real. If b²-4ac is a perfect square, the solutions are real and rational; otherwise they’re real but irrational.
If b² < 4ac the solutions are complex.
7 0
3 years ago
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