The number of real zeros of the function f(x) = x3 + 4x2 + x − 6 is 3
<h3>How to determine the number of real zeros?</h3>
The equation of the function is given as:
Expand the function
Reorder the terms
Factor the expression
Factor out x -1
Expand
Factorize
](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5Bx%28x%20%2B%203%29%20%2B%202%28x%20%2B%203%29%5D%28x%20-%201%29)
Factor out x + 2
The function has been completely factored and it has 3 linear factors
Hence, the number of real zeros of the function f(x) = x3 + 4x2 + x − 6 is 3
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Answer:
1/3* (9x-6) = 2x+3
⇒ (1/3)(9x)- (1/3)*6 = 2x+3 (distributive property)
⇒ 3x - 2= 2x + 3
⇒ (3x-2x) -2 = (2x-2x) +3
⇒ x-2=3
⇒ x +(-2+2) = 3+2
⇒ x= 5.
Step-by-step explanation:
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Answer:
he bought 6 hats.
Step-by-step explanation:
im just gonna go through this 1 at a time. starting at 1.
12 + (14x9) = 138
(12x5)+(14x5) = 130
(12x4)+(14x6) = 132
(12x8)+(14x2) = 124
(12x6)+(14x4) = 128
A is at -8 and C i5 at 5
-8 to 0 is 8 units and 0 to 5 is 5 units.
8 +5 = 13
AC is 13 units long.
If the temperature dropped by 7.f each hour from 5:00 am to 9:00 am. the beginning temperature at 5:00 am if the temperature at 9:00 am was -10.f is 18.f.
<h3>
Beginning temperature</h3>
Dropped in temperature=7.t
Number of hours= 5:00 am to 9:00 am=4 hours
Temperature at 9:00 am=-10.f
Hence:
Beginning temperature can be calculated as:
Beginning temperature=(4× 7) + (-10)
Beginning temperature=28 + (-10)
Beginning temperature= 18.f
Check:
Since temperature dropped by 7.f each hour from 5:00 am to 9:00 am
which implies that temperature 7.f dropped for 4 hours.
Hence:
18-7-7-7-7=-10.f
Therefore If the temperature dropped by 7.f each hour from 5:00 am to 9:00 am. the beginning temperature at 5:00 am if the temperature at 9:00 am was -10.f is 18.f.
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