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Bad White [126]
4 years ago
7

What is the greatest possible number of real zeros of f(x) = x3 – 2x2-x+1?

Mathematics
1 answer:
Sedaia [141]4 years ago
6 0

Answer:

Step-by-step explanation:Use the drop-down menus to identify the roots in these English words.

Aristocratic:  

Incredulous:  

Contradiction:  

Regeneration:  

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Leon is making punch for his birthday party. First, he pours 20 cups of ginger ale into his punch bowl. Then, he adds two 64-flu
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Answer: 28 cups.

Step-by-step explanation: If he has already poured 20 cups then 64 fluid ounces, 8 fluid ounces makes a cup. 8 x 8 is 64. So the answer is 8, after you do that you add it to the 20 and you have your answer.

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You can tell if the value of a function for a certain interval is positive just by 2 points looking at its graph. If the value i
Scilla [17]
It is b. above the x axis
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Find all real zeros of the function. <br> f(x)=4(x^2-1)(x-3)(x+3)^2
prisoha [69]
4(x^2 - 1)(x - 3)(x + 3)^2 = 0
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3 years ago
What is the perimeter of P:(2,2) Q:(6,2) R:(6,5) S:(2,5)
almond37 [142]

Answer: 14

Step-by-step explanation:

P(6)- Q(2) = 4

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Brainliest is appericiated!

5 0
3 years ago
Read 2 more answers
. Find the smallest value of k such that 3240k is a perfect cube.
Stels [109]
The product of multiple perfect cubes is also a perfect cube.
Proof for two:
n^3 * p^3 = nnnppp = npnpnp = (np)^3
And any integer whose exponent is a multiple of 3 is a perfect cube.
We will use this here:

Prime factorize 3240:
3240 = 405 * 2^3 = 2^3 * 3^4 * 5^1
We need to multiply this by k, to make all the exponents divisible by 3
The exponents not divisible by 3 are 4 and 1.
So let's fix that:
2^3 * 3^4 * 3*2 * 5^1 * 5^2
So, k is 3^2 * 5^2 = 225
(3240*225)^(1/3) = 90
8 0
3 years ago
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