Answer:
x=24
y=24
Step-by-step explanation:
I hope this helps
What is the greatest possible number of real zeros of f(x) = x3 – 2x2-x+1?
1 answer:
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Answer:
The answer to your question
a) Values excluded = -2, 0
b) solutions = -2/3, 2
Step-by-step explanation:
Equation
a) x is restricted when the denominators equal zero, so let's get them.
2x + 4 = 0 2x = 0
2x = - 4 x = 0 / 2
x = -4 / 2 x = 0
x = -2
x must be different to -2, 0
b)
4x² = (x + 2)²
4x² = x² + 4x + 4
4x² - x² - 4x - 4 = 0
3x² - 4x - 4 = 0
3x² - 6x + 2x - 4 = 0
3x(x - 2) + 2(x - 2) = 0
(x - 2)(3x + 2) = 0
x₁ - 2 = 0 3x₂ + 2 = 0
x₁ = 2 x₂ = -2/3
