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3 years ago

20. One factor of x^3 + 2x^2 – 23x - 60 is x +4. Find the remaining factors.

Mathematics

2 answers:

lapo4ka [179]3 years ago

8 0

Answer: use x+4 to divide x³+2x²-23x-60

x² -2x-15

__________

x+4 √x³+2x²-23x-60

-(x³+4x²)

-2x²-23x-60

-(-2x²-8x)

-15x-60

-(-15x-60)

Factorize x²-2x-15

x²-5x+3x-15

x(x-5)+3(x-5)

(x-5)(x+3)

Step-by-step explanation:

hammer [34]3 years ago

6 0

Answer:

x – 5 and x + 3

Step-by-step explanation:

Knowing that x + 4 is a factor, we can use grouping to factor:

x³ + 2x² – 23x – 60

x³ + 2x² – 8x – 15x – 60

x (x² + 2x – 8) – 15 (x + 4)

x (x – 2) (x + 4) – 15 (x + 4)

(x (x – 2) – 15) (x + 4)

(x² – 2x – 15) (x + 4)

(x – 5) (x + 3) (x + 4)

To use long division, see attached image.

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3 years ago

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elena-14-01-66 [18.8K]

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Step-by-step explanation:

I think the only way you can solve this is to assume that <R means PRT in the given ratio. If I am wrong, I don't think the problem can be solved.

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mixer [17]

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