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anyanavicka [17]
3 years ago
14

A 3 kg block is pulled with a force of 45 b along with frictionless horizontal surface at an angle of 30 degrees what is the hor

izontal force acting on the block
Mathematics
1 answer:
alexgriva [62]3 years ago
8 0

Answer:

Fₐ ≈ 38.97 N

Step-by-step explanation:

The illustration forms a right angle triangle with the horizontal side been the side of horizontal force.

The horizontal component of the applied force can be calculated as follows

Force applied on the block = 45 N

The force on the horizontal is the force of acceleration use to pull the block .

Fₐ = 45 N cos 30°

The formula is gotten by using the cosine ratio of the right angle triangle formed.

Recall

cos 30° = adjacent/hypotenuse

Fₐ = 45 N cos 30°

Fₐ = 45 × cos 30°

Fₐ = 45 × 0.86602540378

Fₐ = 38.9711431703

Fₐ ≈ 38.97 N

 

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Cable Strength: A group of engineers developed a new design for a steel cable. They need to estimate the amount of weight the ca
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Answer:

95% confidence interval for the mean breaking strength of the new steel cable is [763.65 lb , 772.75 lb].

Step-by-step explanation:

We are given that the engineers take a random sample of 45 cables and apply weights to each of them until they break. The mean breaking weight for the 45 cables is 768.2 lb. The standard deviation of the breaking weight for the sample is 15.1 lb.

Since, in the question it is not specified that how much confidence interval has be constructed; so we assume to be constructing of 95% confidence interval.

Firstly, the Pivotal quantity for 95% confidence interval for the population mean is given by;

                            P.Q. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean breaking weight = 768.2 lb

            s = sample standard deviation = 15.1 lb

            n = sample of cables = 45

            \mu = population mean breaking strength

Here for constructing 95% confidence interval we have used One-sample t test statistics as we don't know about population standard deviation.

<u>So, 95% confidence interval for the population mean, </u>\mu<u> is ;</u>

P(-2.02 < t_4_4 < 2.02) = 0.95  {As the critical value of t at 44 degree

                                           of freedom are -2.02 & 2.02 with P = 2.5%}  

P(-2.02 < \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } } < 2.02) = 0.95

P( -2.02 \times {\frac{s}{\sqrt{n} } } < {\bar X-\mu} < 2.02 \times {\frac{s}{\sqrt{n} } } ) = 0.95

P( \bar X-2.02 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X+2.02 \times {\frac{s}{\sqrt{n} } } ) = 0.95

<u>95% confidence interval for</u> \mu = [ \bar X-2.02 \times {\frac{s}{\sqrt{n} } } , \bar X+2.02 \times {\frac{s}{\sqrt{n} } } ]

                                     = [ 768.2-2.02 \times {\frac{15.1}{\sqrt{45} } } , 768.2+2.02 \times {\frac{15.1}{\sqrt{45} } } ]

                                     = [763.65 lb , 772.75 lb]

Therefore, 95% confidence interval for the mean breaking strength of the new steel cable is [763.65 lb , 772.75 lb].

3 0
3 years ago
In ben's class, there were five exams given throughout the semester. if the average of his first four exams was a 90, what was h
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Number of exams per semester = 5
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Therefore,
Total of first four exams = 90*4 = 360 marks

Based on 5 exams,

Average = 360/5 = 72
6 0
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