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Stolb23 [73]
3 years ago
15

Solve equation 13=x/7+5

Mathematics
2 answers:
Korolek [52]3 years ago
6 0
(7) X/7+5=13 (7) multipl 7 to cancel the division

49x+5= 91
-5. -5. Subtract 5 to get X by itself

49x = 86
—————
49. 49. Divide number with X to 86

X = 1.76 if round to the hundredth solution
yuradex [85]3 years ago
3 0

Answer:

56

Step-by-step explanation:

Isolate the variable (x). Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS.

First, subtract 5 from both sides:

13 (-5) = (x/7) + 5 (-5)

13 - 5 = x/7

8 = x/7

Isolate the variable x. Multiply 7 to both sides:

8(7) = (x/7)(7)

8(7) = x

x = 8 * 7

x = 56

56 is your answer for x.

~

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How do you simplify this?<br>x²y+xy² / y²+2/5 × xy​​​
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\huge \boxed{\mathbb{QUESTION} \downarrow}

  • How do you simplify this?
  • x²y+xy² / y²+2/5 × xy

\large \boxed{\mathbb{ANSWER\: WITH\: EXPLANATION} \downarrow}

\sf\frac{  { x  }^{ 2  }  y+x { y  }^{ 2  }    }{  { y  }^{ 2  }  + \frac{ 2  }{ 5  }   \times  xy  } \\

Factor the expressions that are not already factored.

_____

<u>How </u><u>to</u><u> factorise</u><u> </u><u>:</u><u>-</u>

<u>NUMERATOR</u> \downarrow

\sf \: x ^ { 2 } y + x y ^ { 2 }

Factor out xy.

\sf \: xy\left(x+y\right)

<u>DENOMINATOR</u> \downarrow

\sf{ y  }^{ 2  }  + \frac{ 2  }{ 5  }   \times  xy \\

Factor out 1/5.

\sf \: {\frac{1}{5}y\left(2x+5y\right)}  \\

_____

Continuing...

\sf\frac{xy\left(x+y\right)}{\frac{1}{5}y\left(2x+5y\right)}  \\

Cancel out y in both the numerator and denominator.

\sf\frac{x\left(x+y\right)}{\frac{1}{5}\left(2x+5y\right)}  \\

Expand the expression.

\sf\frac{x^{2}+xy}{\frac{2}{5}x+y}  \\

This can further simplified to as \downarrow

=    \boxed{\boxed{\bf\frac{5x\left(x  +y\right)}{2x+5y}}}

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