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Aleonysh [2.5K]
2 years ago
8

Mia wrote an equation to approximate the total number of calories in the strawberries she was eating. She used the equation y =

5.5 x, where y represents the total number of calories and x represents the number of strawberries she was eating. Which graph represents this information?
Calories in Strawberries
On a coordinate plane, the x-axis is labeled number of strawberries and the y-axis is labeled total calories. A line goes through points (1, 5) and (9, 50).
Calories in Strawberries
On a coordinate plane, the x-axis is labeled number of strawberries and the y-axis is labeled total calories. A line goes through points (1, 5) and (10, 2).
Calories in Strawberries
On a coordinate plane, the x-axis is labeled number of strawberries and the y-axis is labeled total calories. A line goes through points (3, 1) and (8, 3).
Calories in Strawberries
On a coordinate plane, the x-axis is labeled number of strawberries and the y-axis is labeled total calories. A line goes through points (1, 3) and (3, 8).
Mathematics
2 answers:
kifflom [539]2 years ago
6 0

Answer: I think b but don’t take my word

Step-by-step explanation:

borishaifa [10]2 years ago
4 0

Answer:

Yea, I'm pretty sure It's B.

It makes the most sense.

Hope this helps!

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lutik1710 [3]

Answer:

4.1

Step-by-step explanation:

6 0
2 years ago
Can any one help me on this? Please thank you
nignag [31]
The area of a triangle is base length x height then divide all by 2, 
so 12 x 10 /2
=60 ft²
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2 years ago
Peter has four horses.Each one eats 4 pounds of oats,twice a day.How many pounds of oats does he need to feed his horses for 3 d
Kobotan [32]
4 pound of oats twice a day= 8 pounds of oats each day per horse. He has 4 horses so 4 horses times 8 pounds of oats is 32. You multiply 32 pounds times the three days he has to feed which is 96 pounds.
8 0
3 years ago
Read 2 more answers
The points A(1, 4), B(5,1) lie on a circle. The line segment AB is a chord. Find the equation of a diameter of the circle.
tangare [24]

Check the picture below.

well, we want only the equation of the diametrical line, now, the diameter can touch the chord at any several angles, as well at a right-angle.

bearing in mind that <u>perpendicular lines have negative reciprocal</u> slopes, hmm let's find firstly the slope of AB, and the negative reciprocal of that will be the slope of the diameter, that is passing through the midpoint of AB.

\bf A(\stackrel{x_1}{1}~,~\stackrel{y_1}{4})\qquad B(\stackrel{x_2}{5}~,~\stackrel{y_2}{1}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{1}-\stackrel{y1}{4}}}{\underset{run} {\underset{x_2}{5}-\underset{x_1}{1}}}\implies \cfrac{-3}{4} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{slope of AB}}{-\cfrac{3}{4}}\qquad \qquad \qquad \stackrel{\textit{\underline{negative reciprocal} and slope of the diameter}}{\cfrac{4}{3}}

so, it passes through the midpoint of AB,

\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ A(\stackrel{x_1}{1}~,~\stackrel{y_1}{4})\qquad B(\stackrel{x_2}{5}~,~\stackrel{y_2}{1}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{5+1}{2}~~,~~\cfrac{1+4}{2} \right)\implies \left(3~~,~~\cfrac{5}{2} \right)

so, we're really looking for the equation of a line whose slope is 4/3 and runs through (3 , 5/2)

\bf (\stackrel{x_1}{3}~,~\stackrel{y_1}{\frac{5}{2}}) \stackrel{slope}{m}\implies \cfrac{4}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{\cfrac{5}{2}}=\stackrel{m}{\cfrac{4}{3}}(x-\stackrel{x_1}{3})\implies y-\cfrac{5}{2}=\cfrac{4}{3}x-4 \\\\\\ y=\cfrac{4}{3}x-4+\cfrac{5}{2}\implies y=\cfrac{4}{3}x-\cfrac{3}{2}

4 0
3 years ago
Simifyimg expressions pleaseeeeeeeee help me please I'm begging
seraphim [82]
   -3(6-10v-5v)
=-3(6-15v)
=-18+45v
-18+45v is the final answer.
8 0
3 years ago
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