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ololo11 [35]
4 years ago
15

The length of a train car is 50.6 feet. This is 5.8 feet less than 6 times the width. What is the width? Round to the nearest te

nth.
Mathematics
1 answer:
Anon25 [30]4 years ago
4 0
The answer would be 9.4.
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How to make an improper fraction into a proper fraction?
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Divide the numerator by the denominator and any remaining values go back above the denominator. 

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Step-by-step explanation:

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Complete the table for the given rule.<br> Rule: y = x + 8<br> (there’s and image with the problem.)
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A new post-surgical treatment is being compared with a standard treatment. Seven subjects receive the new treatment, while seven
a_sh-v [17]

Answer:

(17.714-28.714) -2.681 \sqrt{\frac{4.461^2}{7} +\frac{7.387^2}{7}}= -19.745

(17.714-28.714) +2.681 \sqrt{\frac{4.461^2}{7} +\frac{7.387^2}{7}}= -2.255

Step-by-step explanation:

For this case we have the following info given:

Treatment: 12 13 15 19 20 21 24

Control: 18 23 24 30 32 35 39

We can find the sample mean and deviations with the the following formulas:

\bar X = \frac{\sum_{i=1}^n X_i}{n}

s =\sqrt{\frac{\sum_{i=1}^n (X_i- \bar X)^2}{n-1}}

And repaplacing we got:

\bar X_T = 17.714 the sample mean for treatment

\bar X_C = 28.714 the sample mean for treatment

s_T= 4.461 the sample deviation for treatment

s_C= 7.387 the sample deviation for control

n_T= n_C= 7 the sample size for each sample

The degrees of freedom are given by:

df= 7+7-2= 12

The confidence interval for the difference of means is given by:

(\bar X_T -\bar X_C) \pm t_{\alpha/2} \sqrt{\frac{s^2_T}{n_T} +\frac{s^2_C}{n_C}}

The confidence is 98% so then the significance is \alpha=0.02 and \alpha/2 =0.01. Then the critical value would be:

t_{\alpha/2}=2.681

And replacing we got:

(17.714-28.714) -2.681 \sqrt{\frac{4.461^2}{7} +\frac{7.387^2}{7}}= -19.745

(17.714-28.714) +2.681 \sqrt{\frac{4.461^2}{7} +\frac{7.387^2}{7}}= -2.255

4 0
4 years ago
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