Answer: 0.001 or 1/1000
Since it is a negative exponent and -3 so it is in the thousandths, so 1/1000 or 0.001.
Have a good day! : )
Answer:
a. 35 degrees
b. 145 degrees
Step-by-step explanation:
a. Since the two base angles of this triangle are congruent, we can conclude that the triangle is <em>isosceles, </em>which means that the two base angles and sides are congruent.
Now, knowing that information, we can subtract 110 from 180 (the sum of all interior angles in a triangle) and we get 70. But this isn't our answer. This is the sum of both base angles. Since the base angles are congruent, we can divide the 70 by 2 to get the measure of ONE base angle, which is 35 degrees.
b. There are two approaches to solve this problem. I have worked both out.
1) We can use the Exterior Angle Theorem, which states that the sum of the interior angles is equal to the exterior angle. We can add 110 to 35, so we get 145 degrees as the measure of <1.
2) The second approach is supplementary angles. Since we see that one of the base angles and <1 is on the same line, we can subtract 35 from 180 to find the measure of <1 to get 145 degrees.
Either way you use, you get the correct answer. Hope this helped!
The equation for point slope form is written as :
y - y1 =m(x-x1)
M is the slope which is given as -37
The given point would be X1 and y1, where X1 is 5 and y1 is 8.
The equation becomes:
y - 8 = -37(x -5)
Answer:
Follows are the solution to the given points:
Step-by-step explanation:
Given value:
For point a:
Moment generating function of X=?
Using formula:
integrating the values by parts:
![u = x \\\\dv = e^{(t-1)x}\\\\dx =dx \\\\v= \frac{e^{(t-1)x}}{t-1}\\\\M(t) =[\frac{e^{(t-1)x}}{t-1}]^{-\infty}_{0} -\int^{\infty}_{0} \frac{e^{(t-1)x}}{t-1} \ dx\\\\](https://tex.z-dn.net/?f=u%20%3D%20x%20%5C%5C%5C%5Cdv%20%3D%20e%5E%7B%28t-1%29x%7D%5C%5C%5C%5Cdx%20%3Ddx%20%5C%5C%5C%5Cv%3D%20%5Cfrac%7Be%5E%7B%28t-1%29x%7D%7D%7Bt-1%7D%5C%5C%5C%5CM%28t%29%20%3D%5B%5Cfrac%7Be%5E%7B%28t-1%29x%7D%7D%7Bt-1%7D%5D%5E%7B-%5Cinfty%7D_%7B0%7D%20%20-%5Cint%5E%7B%5Cinfty%7D_%7B0%7D%20%5Cfrac%7Be%5E%7B%28t-1%29x%7D%7D%7Bt-1%7D%20%5C%20dx%5C%5C%5C%5C)
![= \frac{1}{t-1} (0) - [\frac{e^{(t-1)x}}{(t-1)^2}]^{\infty}_{0}\\\\=\frac{1}{(t-1)^2}(0-1)\\\\=\frac{1}{(t-1)^2}\\\\](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B1%7D%7Bt-1%7D%20%280%29%20-%20%5B%5Cfrac%7Be%5E%7B%28t-1%29x%7D%7D%7B%28t-1%29%5E2%7D%5D%5E%7B%5Cinfty%7D_%7B0%7D%5C%5C%5C%5C%3D%5Cfrac%7B1%7D%7B%28t-1%29%5E2%7D%280-1%29%5C%5C%5C%5C%3D%5Cfrac%7B1%7D%7B%28t-1%29%5E2%7D%5C%5C%5C%5C)
Therefore, the moment value generating by the function is 
In point b:
Using formula:
form point (a):
Differentiating the value with respect of t
when 
