Speed=distance/time suppose the distance of the first day is d, and the time is t distance of the second day: d+0.17d=1.17d time of the second day: t+0.2t=1.2t speed of the second day: 1.17d/1.2t=0.975(d/t)=(1-0.025)(d/t) so the speed of the second day is 2.5% slower than the first day.