Question

the area of a rectangular volleyball court is 1800 square feet the courts length is twice it width write a system of equations that could be used to determine the dimensions in feet of the volleyball court

Answer 1

Answer:

The dimensions of the rectangular volleyball court are 60 ft x 30 ft

Step-by-step explanation:

Let

x ----> the length of rectangular volleyball court

y ---> the width of the rectangular volleyball court

we know that

The area of the rectangular volleyball court is equal to

$A=xy$

$A=1,800\ ft^2$

so

$1,800=xy$ ----> equation A

$x=2y$ -----> equation B

substitute equation B in equation A

$1,800=(2y)y$

$1,800=2y^2$

Solve for y

Simplify

$900=y^2$

take square root both sides

$y=30\ ft$

Find the value of x

$x=2y$

substitute the value of y

$x=2(30)=60\ ft$

therefore

The dimensions of the rectangular volleyball court are 60 ft x 30 ft