Answer:
We draw line AB which is perpendicular to the 14 cm side
Since Angle C is 60 degrees that makes angle CAB = 30 degrees
Triangle CAB is a 30 60 90 triangle so line CB is half the hypotenuse or 5 cm
Line BD equals 9 cm
Line AB^2 = 10^2 - 5^2 = 75
Line AD^2 = AB^2 + BD^2
Line AD^2 = 75 + 81
Line AD^2 = 156
Line AD = 12.4899959968
Line AB = Sqr root (75) = 8.6602540378
Angle D = arc sine (8.6602540378 / 12.4899959968)
Angle D = 43.898 degrees
Angle A = 180 - 60 - 43.898 = 76.102 degrees
*****************************************************************
Actually this could have been done a little easier by using the Law of Cosines and then the Law of Sines, but I just thought I'd show another way to solve this.
Step-by-step explanation:
Step-by-step explanation:
y=-3/4 ÷ -4/3
y=+9/16
<span>If 3x-1=11, then 2x=?
</span><span>
2x + x - 1 = 11
2x = -x +12</span>
Answer:
Weight of parcel to the nearest whole kilogram = 6 kg
Explanation:
Weight of parcel = 12 lbs 8 oz
1lb = 16 oz also we have 1lb = 454 g
Weight of parcel = 12 lbs 8 oz = 12 + (8/16) lbs = 12.5 lbs
Weight of parcel in g = 12.5*454 = 5675 g
Weight of parcel = 5675 g = 5.675 kg
Weight of parcel to the nearest whole kilogram = 6 kg