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3 years ago

14

What is the reference angle for the angle with measure −π4?

2 answers:

Jet001 [13]3 years ago

7 0

Answer:

What is the reference angle for the angle with measure −π/4?

Answer: n/4

pie/4

Step-by-step explanation:

I just took the test lol the other answer is wrong.

tresset_1 [31]3 years ago

6 0

Answer:

D -7π4

Step-by-step explanation:

Just took the test my dude :D

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Please can someone help me with this question.

saw5 [17]

Answer:

Step-by-step explanation:

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2 years ago

How do you find the area of a triangle when given only the lengths of three sides?

SashulF [63]

Answer:

Use Heron's formula; see below.

Step-by-step explanation:

Use Heron's formula.

Let the sides of the triangle have lengths a, b, and c.

$s = \dfrac{a + b + c}{2}$

$area = \sqrt{s(s - a)(s - b)(s - c)}$

Example:

A triangle has side lengths 3, 4, and 5 units.

Find the area of the triangle.

$s = \dfrac{a + b + c}{2}$

$s = \dfrac{3 + 4 + 5}{2}$

$s = 6$

$area = \sqrt{s(s - a)(s - b)(s - c)}$

$area = \sqrt{6(6 - 3)(6 - 4)(6 - 5)}$

$area = \sqrt{6(3)(2)(1)}$

$area = \sqrt{36}$

$area = 6$

3 0

2 years ago

What term describes a pair of vertical angles that are also supplementary: acute obtuse right straight?

IgorC [24]

Your answer would be straight!!

7 0

3 years ago

Read 2 more answers

What is the equation of the following line written in general form? (The y-intercept is -1.)

Ludmilka [50]

Answer:

The correct answer is 2x - y - 1 = 0

Step-by-step explanation:

To find this, use the ordered pair (1, 1) in any of the equations. If it results in a true statement then this can be an equation.

2x - y - 1 = 0

2(1) - (1) - 1 = 0

2 - 1 - 1 = 0

0 = 0 (TRUE STATEMENT)

3 0

3 years ago

Read 2 more answers

PLEASE HELP<br><br>divide. (3x-2)(x-4)-(x-4)(6-5x)<br>/(4-x)(8x-1)

8_murik_8 [283]

Answer:

x = 39/74 - sqrt(1817)/74 or x = 39/74 + sqrt(1817)/74

Step-by-step explanation:

Solve for x:

(x - 4) (3 x - 2) - ((6 - 5 x) (x - 4) (8 x - 1))/(4 - x) = 0

Simplify and substitute y = 4 - x.

(x - 4) (3 x - 2) - ((6 - 5 x) (x - 4) (8 x - 1))/(4 - x) = -434 + 257 (4 - x) - 37 (4 - x)^2

= -37 y^2 + 257 y - 434:

-37 y^2 + 257 y - 434 = 0

Divide both sides by -37:

y^2 - (257 y)/37 + 434/37 = 0

Subtract 434/37 from both sides:

y^2 - (257 y)/37 = -434/37

Add 66049/5476 to both sides:

y^2 - (257 y)/37 + 66049/5476 = 1817/5476

Write the left hand side as a square:

(y - 257/74)^2 = 1817/5476

Take the square root of both sides:

y - 257/74 = sqrt(1817)/74 or y - 257/74 = -sqrt(1817)/74

Add 257/74 to both sides:

y = 257/74 + sqrt(1817)/74 or y - 257/74 = -sqrt(1817)/74

Substitute back for y = 4 - x:

4 - x = 257/74 + sqrt(1817)/74 or y - 257/74 = -sqrt(1817)/74

Subtract 4 from both sides:

-x = sqrt(1817)/74 - 39/74 or y - 257/74 = -sqrt(1817)/74

Multiply both sides by -1:

x = 39/74 - sqrt(1817)/74 or y - 257/74 = -sqrt(1817)/74

Add 257/74 to both sides:

x = 39/74 - sqrt(1817)/74 or y = 257/74 - sqrt(1817)/74

Substitute back for y = 4 - x:

x = 39/74 - sqrt(1817)/74 or 4 - x = 257/74 - sqrt(1817)/74

Subtract 4 from both sides:

x = 39/74 - sqrt(1817)/74 or -x = -39/74 - sqrt(1817)/74

Multiply both sides by -1:

Answer: x = 39/74 - sqrt(1817)/74 or x = 39/74 + sqrt(1817)/74

7 0

3 years ago