Answer:
I'm pretty sure it's (0,1)
The answer needs the volume of the original pyramid minus the small pyramid cut off.
Volume of pyramid = (area of base x height)/3
(12 x 6 x 14)/3 - (4 x 10 x 6)/3 = 256 m^3
The diagram is completely wrong so this problem is actually impossible to solve!
If you slice horizontally across a rectangular pyramid the ratios of the edges will remain constant.
The two rectangles are not the same shape! 12:6 is not the same ratio as 10:4
If the original pyramid in this question was sliced in half the top rectangle of the frustum would be 6 x 3.
In this diagram the height was reduced from 14m to 8m so the top 6m was removed.
If the base was 12 x 6 the top rectangle should be 6/14 smaller = 5.14m by 2.57m (not 10 x 4)
If you are brave you could point this out to your teacher
The best thing to do for this question is to find a common denominator, and the best way to do this is to list all of the multiples and find the smallest common one.
8- 8, 16, 24, 32, 40, 48
20- 20, 40, 60
In this, 40 is the lowest, so you have to multiply 5/8 by 5 at the top and bottom, and this gives you 25/40. You have to multiply the second fraction by 2, and this becomes 22/40.
Therefore, the larger fraction is 5/8.
The alternative method is to turn them into decimals and compare them this way. 5/8= 0.625 & 11/20= 0.55
Hope this helps
A=TX
Rewrite it
Tx=a
Divide t both sides to get x alone
Tx/t=a/t
Solve
X= a/t
