All categories

3 years ago

The formulas for power and work are and , where P= w/t is the power, W= fd

Mathematics

2 answers:

Klio2033 [76]3 years ago

6 0

P = W/t
W = Fd

P = Fd/t = F/t d

Anit [1.1K]3 years ago

6 0

Answer:

the answer is d= power times time divided by the force

so it would d=pt/f

Step-by-step explanation:

You might be interested in

in a survey of 500 voters 430 said they would vote for the same candidate again what percent of the voters would vote the same w

Nina [5.8K]

Answer:

86%

Step-by-step explanation:

430 × 100 = 430 = 86%

500 1 5

you are going to cancel. 100 divided by 100 leaves 1. 500 divided by 100 is 5.

430×1= 430. 5×1=5. divide 430 by 5 and you"ll get 86.

8 0

2 years ago

Read 2 more answers

here is points my children <3 enjoy them just answer the question for the points: regards - drip king.

allochka39001 [22]

Answer:

thxs <3

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

Please help find and plot the reflection of this. I will mark brainliest

lubasha [3.4K]

Answer:

Look below for coordinates

Step-by-step explanation:

A: -2, 3 to A': -2, -3

B: 5, -2 to B': 5, 2

C: -5, 1 to C': -5, -1

Reflect over x-axis: (x, -y) and Reflect over y-axis: (-x, y)

7 0

2 years ago

Giving brainliest to first correct answer:PPP

tia_tia [17]

The correct answer is 317

5 0

2 years ago

Read 2 more answers

Approximate the change in the volume of a sphere when its radius changes from r = 40 ft to r equals 40.05 ft (Upper V (r )equal

alexgriva [62]

Answer:

The change in the volume of a sphere whose radius changes from 40 feet to 40.05 feet is approximately 1005.310 cubic feet.

Step-by-step explanation:

The volume of the sphere ( $V$ ), measured in cubic feet, is represented by the following formula:

$V = \frac{4\pi}{3}\cdot r^{3}$

Where $r$ is the radius of the sphere, measured in feet.

The change in volume is obtained by means of definition of total difference:

$\Delta V = \frac{\partial V}{\partial r}\Delta r$

The derivative of the volume as a function of radius is:

$\frac{\partial V}{\partial r} = 4\pi \cdot r^{2}$

Then, the change in volume is expanded:

$\Delta V = 4\pi \cdot r^{2}\cdot \Delta r$

If $r = 40\,ft$ and $\Delta r = 40\,ft-40.05\,ft = 0.05\,ft$ , the change in the volume of the sphere is approximately:

$\Delta V \approx 4\pi\cdot (40\,ft)^{2}\cdot (0.05\,ft)$

$\Delta V \approx 1005.310\,ft^{3}$

The change in the volume of a sphere whose radius changes from 40 feet to 40.05 feet is approximately 1005.310 cubic feet.

7 0

2 years ago