Answer:
See answer and graph below
Step-by-step explanation:
∬Ry2x2+y2dA
=∫Ry.2x.2+y.2dA
=A(2y+4Ryx)+c
=∫Ry.2x.2+y.2dA
Integral of a constant ∫pdx=px
=(2x+2.2Ryx)A
=A(2y+4Ryx)
=A(2y+4Ryx)+c
The graph of y=A(2y+4Ryx)+c assuming A=1 and c=2
me so sorry come back laterAnswer:
Step-by-step explanation:me so sorry come back later
Answer:
First Equation: 6a-23
Second Equation: 5a-20
Step-by-step explanation:
So, I think you want me to answer part 2...
For the first equation, we can see that the denominator stays the exact same, meaning the numerator will also not change.
For the second equation, we can see the denominator changed from a-3 to 5a-15. The denominator was simply multiplied by 5. Since the denominator was multiplied by five we must multiply the numerator by five as well.
5(a-4)
5a-20
Hope this helps :)
Answer:
B
Step-by-step explanation:
Answer:
10
Step-by-step explanation:
