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vaieri [72.5K]
3 years ago
14

5(2) - (2 + 3)2 = 10 + (-5)2

Mathematics
2 answers:
erik [133]3 years ago
5 0
The answer is 0=0 
5(2)-(2+3)2=10+(-5)2
10-(2+3)2=10+(-5)2
10-10=10+(-5)2
0=10+(-5)2
0=10+-10
0=10-10
0=0

Alona [7]3 years ago
4 0
Infinity Many solutions
end in 0=0
You might be interested in
A radioactive substance decays at a continuous rate of 17% per year, and 250 mg of the substance is present in the year 2009.
yaroslaw [1]

Answer:

a) A(t) = 250 (1-0.17)^t = 250(0.83)^t

b) A(t=14) = 250 (0.83)^{14}= 18.408 mg

c) For this case we want to find when the quantity is below 25 mg, so we can do this:

25 = 250 (0.83)^t

We can divide both sided by 250 and we got:

0.1 = 0.83^t

Now we can apply natural log on both sides and we got:

ln(0.1) = t ln (0.83)

And if we solve for t we got:

t = \frac{ln(0.1)}{ln(0.83)}= 12.358 years

So the answer for this case would be 12.358 years after.

Step-by-step explanation:

Part a

For this case we know that the decay rate per year is about 17% or 0.17 in fraction and the initial amount is 250 mg for 2009, we can define the model like this:

A(t) = A_o (1-r)^t

Where A represent the amount of the substance in mg, r the decay rate = 0.17 and t the number of years after 2009.

Our model for this case would be:

A(t) = 250 (1-0.17)^t = 250(0.83)^t

Part b

For this case we have that t= 2023-2009=14 years, so then we can find the amount of substance like this:

A(t=14) = 250 (0.83)^{14}= 18.408 mg

Part c

For this case we want to find when the quantity is below 25 mg, so we can do this:

25 = 250 (0.83)^t

We can divide both sided by 250 and we got:

0.1 = 0.83^t

Now we can apply natural log on both sides and we got:

ln(0.1) = t ln (0.83)

And if we solve for t we got:

t = \frac{ln(0.1)}{ln(0.83)}= 12.358 years

So the answer for this case would be 12.358 years after.

6 0
3 years ago
YEAR 9 MATHS PLEASE HELP ME
Genrish500 [490]

Answer:

<h2>X = 4.5</h2>

Step-by-step explanation:

So we have two equations.

y=35x+40

y=40x+17.5

We want to find the coordinates in which they intersect.

BUT They never intersect, They are parallel to each other leaving us with a

NO SOLUTION

When you are trying to solve for x you want to get rid of the y's and simply put on your paper:       35x+40 = 40x+17.5

Then you distribute, in which I am not going to show because that too many steps lol. But you'll get:

x=4.5

5 0
4 years ago
Levi works as a salesperson at an electronics store and sells phones and phone accessories. Levi earns a $8 commission for every
Juliette [100K]

8p + 3a = 213 and p + a = 41 are the two required equations which will give us the number of phones and accessories sold by Levi.

<u>Solution:</u>

Levi earns a $8 commission for every phone he sells and a $3 commission for every accessory he sells.

On a given day, Levi made a total of $213 in commission from selling a total of 41 phones and accessories.  

We have been asked to write a system of equations that could be used to determine the number of phones sold and the number of accessories sold. We also have to define the variables that you use to write the system.

Let us denote the number of phones as ‘p’ and number of accessories as ‘a’

So, we can write the following equations from the given data:

Given that levi made $ 213 commission

8p + 3a = 213

And,  Levi sold 41 phones and accessories. So we can frame a equation as follows:

p + a = 41

These two equations can be used and solved to determine the number of phones and accessories sold.

5 0
4 years ago
Let f(x)=11-3xm compute f(2)+f^-1(2)
Ganezh [65]
Taking f(X) to be y
Y = 11 - 3X
3X = 11 - y
X  = (11-y)÷3
F^-1(x) = (11 - x)÷3 addING both equations
It gives = 0

Please mark as brainliest
8 0
3 years ago
Whats the answer ? I need helllpppppp
Digiron [165]
I don't know. But goodluck with finding the answer.
4 0
4 years ago
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