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LenaWriter [7]
3 years ago
7

A square ceiling has a diagonal of 23 ft. Shelton wants to put molding around the perimeter of the ceiling. The molding is sold

by the foot. What is the minimum amount of molding he needs? 66 ft 65 ft 17 ft 16 ft
Mathematics
2 answers:
marin [14]3 years ago
8 0

Answer:

short answer 66

Step-by-step explanation:

Hatshy [7]3 years ago
6 0

Answer:

Minimum 66 feet of molding that he needs.

Step-by-step explanation:

Given that a square ceiling has a diagonal of 23 ft.

If the sides of the square ceiling are 'a' feet, then applying Pythagoras Theorem we can write, a² + a² = 23²

⇒ 2a² = 23²

⇒ a = 16.2634 feet (Approximate)

Now, the perimeter of the square ceiling will be 4a = 65.05 feet.

If the cost of molding along the perimeter of the ceiling is in per foot, then a minimum of 66 feet of molding that he needs. (Answer)

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3 years ago
Solve for x.
Oksanka [162]

Answer:

x = -4037/127

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

Step-by-step explanation:

<u>Step 1: Define</u>

14x + 18 + x = -112(x + 36) + 13

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Distribute -112:                         14x + 18 + x = -112x - 4032 + 13
  2. Combine like terms:                15x + 18 = -112x - 4019
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  4. Isolate <em>x</em> term:                          127x = -4037
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Vikentia [17]

Answer:

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Odd = 1 ,3 , 5

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