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4 years ago

What is 0.156 divided by 1.2 please explain

Mathematics

2 answers:

ICE Princess25 [194]4 years ago

7 0

0.156 divided by 1.2 is 0.13

amid [387]4 years ago

3 0

The answer is 0.13
If you have a calculator, its easier because of the decimals

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Suppose there are two individuals, Casey and Rick, who live in a very simplified world where only two goods are produced and con

TiliK225 [7]

The answer you should get is 150

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4 years ago

Given $m\geq 2$, denote by $b^{-1}$ the inverse of $b\pmod{m}$. That is, $b^{-1}$ is the residue for which $bb^{-1}\equiv 1\pmod

goblinko [34]

$(2+3)^{-1}\equiv5^{-1}\pmod7$ is the number L such that

$5L\equiv1\pmod7$

Consider the first 7 multiples of 5:

5, 10, 15, 20, 25, 30, 35

Taken mod 7, these are equivalent to

5, 3, 1, 6, 4, 2, 0

This tells us that 3 is the inverse of 5 mod 7, so L = 3.

Similarly, compute the inverses modulo 7 of 2 and 3:

$2a\equiv1\pmod7\implies a\equiv4\pmod7$

since 2*4 = 8, whose residue is 1 mod 7;

$3b\equiv1\pmod7\implies b\equiv5\pmod7$

which we got for free by finding the inverse of 5 earlier. So

$2^{-1}+3^{-1}\equiv4+5\equiv9\equiv2\pmod7$

and so R = 2.

Then L - R = 1.

6 0

3 years ago

(-1/4x-2/3)-(1/2x+1/6) show work no troll answers mark brainlest.

cricket20 [7]

Answer:

if you want it in standard form it would be −1/4x-1/2x-5/6

If you want it simplified it would be -3x/4-5/6

Step-by-step explanation:

(This is the best you'll get for 5 points)

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3 years ago

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3 years ago

The Weibull distribution is widely used in statistical problems relating to aging of solid insulating materials subjected to agi

fenix001 [56]

Answer:

Step-by-step explanation:

Given that

$\alpha =2.5$ , $\beta =220$

The weibull distribution with parameters $\alpha \ \ and \ \ \beta$

where $\alpha =0 \ \ , \beta =0$

$F(x,\alpha ,\beta) \left|\begin{array}{cc}\frac{\alpha }{\beta } x^{\alpha-1e^-(x/\beta)^\alpha &x\geq 0\\0&x$

Then,

$F(x,\alpha ,\beta )=\left|\begin{array}{cc}0&x$

A) The probability that a specimen's lifetime is at most 250 is

$P(X\leq 250)=F(250,2.7,220)\\\\=1-e^-^(250/220)^{2.7}\\\\=1-0.2436\\\\=0.7564$

The probability that the specimen's life time is more than 300 is

$P(X>300)=1-P(X\leq 300)\\\\=1-F(300;2.7,220)\\\\=1-(1-e^-^{(300/220)^{2.7}$

$=e^-^{(300/220)^{2.7}$

= 0.0992

b)The probability of the specimen's lifetime is between 100 and 250

$P(100$

c) The value such that exactly 50% of all specimens have lifetimes exceeding that value is

$P(X>x)=0.50\\\\1-P(X$

x = 192.07

7 0

3 years ago