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sukhopar [10]
3 years ago
10

What is the area of an equilateral triangle with sides of 10 inches and height of 7 inches? A. 70 sq. in. B. 35 sq. in. C. 20 sq

. in. D. 44 sq. in.
Mathematics
2 answers:
erastovalidia [21]3 years ago
8 0

Answer:

the correct answer is 35

Step-by-step explanation:


Ahat [919]3 years ago
5 0
We are given the sides of an equilateral triangle of 10 inches length of the sides and 7 inches as the height of the triangle. The area of the triangle is 0.5*b*h equal to 35 square inches. The answer is 35 square inches in this problem. 
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Answer:

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Step-by-step explanation:

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Andreyy89
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Find the equation of the line through point (1,−5) and perpendicular to y=1/8x+2. Use a forward slash (i.e. "/") for fractions (
Masteriza [31]

Answer:

y = -8x + 3

Step-by-step explanation:

Equation of a line:

The equation of a line has the following format:

y = mx + b

In which m is the slope and b is the y-intercept.

Perpendicular lines:

When two lines are perpendicular, the multiplication of their slopes is -1.

Perpendicular to y=1/8x+2

This line has slope \frac{1}{8}

So, for the line we want to find the equation, we have that:

\frac{m}{8} = -1

m = -8

So

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Find the equation of the line through point (1,−5)

This means that when x = 1, y = -5. We use this to find b. So:

y = -8x + b

-5 = -8 + b

b = 3

The equation of the line is:

y = -8x + 3

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The perimeter of the triangular park shown on the right is 14x-5. What is the missing​ length?
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Answer:70

Step-by-step explanation:

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A point has: no shape no color no size no physical characteristics all of the above
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