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sukhopar [10]
2 years ago
10

What is the area of an equilateral triangle with sides of 10 inches and height of 7 inches? A. 70 sq. in. B. 35 sq. in. C. 20 sq

. in. D. 44 sq. in.
Mathematics
2 answers:
erastovalidia [21]2 years ago
8 0

Answer:

the correct answer is 35

Step-by-step explanation:


Ahat [919]2 years ago
5 0
We are given the sides of an equilateral triangle of 10 inches length of the sides and 7 inches as the height of the triangle. The area of the triangle is 0.5*b*h equal to 35 square inches. The answer is 35 square inches in this problem. 
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Consider the solution to the linear equation. 5 (x + 6) = 50. 5 x + 30 = 50. 5 x = 20. x = 4. Which describes the inverse operat
dem82 [27]

(trying to isolate/get x by itself in the equation)

5(x + 6) = 50      Distributive property   [distribute 5 into (x + 6)]

5x + 30 = 50    Subtraction    [subtract 30 on both sides of the equation]

5x = 20       Division     [divide 5 on both sides]

x = 4

Subtraction then division, the 2nd option

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B
denis23 [38]

Answer:

C. 5units

Step-by-step explanation:

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What is 160% of 80kg
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Answer:

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Step-by-step explanation:

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A boy has 3 red , 2 yellow and 3 green marbles. In how many ways can the boy arrange the marbles in a line if: a) Marbles of the
Ilya [14]

Answer:

The total number of different arrangements is 560.

Step-by-step explanation:

A multiset is a collection of objects, just like a set, but can contain an object more than once.

The multiplicity of a particular type of object is the number of times objects of that type appear in a multiset.

Permutations of Multisets Theorem.

The number of ordered n-tuples (or permutations with repetition) on a collection or multiset of n objects, where there are k kinds of objects and object kind 1 occurs with multiplicity n_1, object kind 2 occurs with multiplicity n_2, ... , and object kind k occurs with multiplicity n_k is:

                                                 \begin{equation*}\frac{n!}{n_1!*n_2!*\dots * n_k!}\end{equation*}

We know that a boy has 3 red, 2 yellow and 3 green marbles. In this case we have n = 8.

If marbles of the same color are indistinguishable, then the total number of different arrangements is

{8 \choose 3, 2, 3}  = \frac{8 !}{3 ! 2 ! 3 !} = \frac{8\cdot \:7\cdot \:6\cdot \:5\cdot \:4}{2!\cdot \:3!}=\frac{6720}{2!\cdot \:3!}=\frac{6720}{12}=560

8 0
2 years ago
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